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andreev551 [17]
3 years ago
7

Please help me with this math word problem

Mathematics
1 answer:
hjlf3 years ago
3 0
Answer: The cost of 16 pencils and 10 notebooks is $5.84.


Explanation: You can solve this using linear systems:

Let X be the cost per pencil, and let Y be the cost per notebook.

(1) 7x+8y=4.15
(2) 5x+3y=1.77

Choose a variable to eliminate. I’ll eliminate X first as an example. To eliminate a variable, you must have the same coefficient beside the variable for both equations.

Equation 1 now becomes:

(3) 35x+40y=20.75

Equation 2 now becomes:

(4) 35x+21y=12.39

Now that you have 35 as a coefficient for X in both equations, you can subtract the two equations to officially eliminate it!

(3)-(4)

19y=8.36
y=0.44

Now that you have the value of Y, substitute that value into either one of the equations to get X.

Substitute y=0.44 in (1)

7x+8(0.44)=4.15
7x+3.52=4.15
7x=0.63
x=0.09

Therefore, the cost per pencil is $0.09/pencil and the cost per notebook is $0.44/notebook.

Almost done lol...

To find the cost of 16 pencils, multiply 0.09*16. That gives you $1.44, which will be the cost of 16 pencils.
The cost of 10 notebooks is 0.44*10, which gives you $4.40. That’s the cost of 10 notebooks.

To find the total price, add these values together!

1.44+4.40=5.84

Therefore, the cost of 16 pencils and 10 notebooks is $5.84.

Hope that helps シ
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Answer:

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Answer: one solution

Step-by-step explanation:

CONCEPT:

- One solution is when the final variable would be able to find a solution.

- Infinite solution is when the equations result in 0=0, meaning any number will fit

- No solution is when the equation results in both sides on equal.

SOLVE:

Given

3/4x-7=3(1/6x+1)

Expand Parenthesis

3/4x-7=1/2+3

Multiply both sides by the LCM of fractions (Least Common Multiple)

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Subtract both sides by 2x

3x-28-2x=2x+12-2x

x-28=12

Add both sides by 28

x-28+28=12+28

x=40

Since we are able to get exactly one solution, there is only one solution.

Hope this helps!! :)

Please let me know if you have any quesionts

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