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2 years ago

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En la regla de la potencia, durante el proceso de integración, se ____ 1 al exponente, mientras que en la derivación se

____ 1 a dicho exponente. De igual forma, el exponente pasa dividiendo mientras que en la derivación pasa ________. Al último, agregamos la letra c, que significa constante" *

1 answer:

Gnesinka [82]2 years ago

8 0

Answer:

a) <em>adiciona</em>, b) <em>sustrae</em>, c) <em>multiplicando</em>.

Step-by-step explanation:

A continuación, presentamos la respuesta correcta al ejercicio citado:

En la regla de la potencia, durante el proceso de integración, se <em>adiciona</em> 1 al exponente, mientras que en la derivación se <em>sustrae</em> 1 a dicho exponente. De igual forma, el exponente pasa dividiendo mientras que en la derivación pasa <em>multiplicando</em>. Al último, agregamos la letra C, que significa constante.

Razones

Derivación de una función potencial:

$\frac{d}{dx}(x^{n}) = n\cdot x^{n-1}, n\ne 0$

Integración de una función potencial:

$\int {x^{n}} \, dx = \frac{x^{n+1}}{n+1}+C,x\ne -1$

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We can find the individual probabilities:

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Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

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$X \sim Binom(n=19, p=0.3)$

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$P(X \geq 5)$

And we can use the complement rule:

$P(X \geq 5)=1-P(X$

We can find the individual probabilities:

$P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114$

$P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092$

$P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358$

$P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869$

$P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491$

And replacing we got:

$P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178$

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Answer:

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