Answer:
2j+j =21
Step-by-step explanation:
if j is Jas
Henry is 2 × Jas; which is 2j
so
j = Jas
2j = Henry
Henry + Jas = 21
input values for Jas and Henry
2j + j = 21
square tan theta
(tan^2) + 1 = sec^2
so sec^2 = 11/4
sec = - (sqrt 11)/2
cos= - 2/ (sqrt 11)
answer choice a if you simplify
Hey there! I'm happy to help!
We want to multiply each term inside the parentheses by the number on the outside.
-3(-7)=21
-3(3z)=-9z
Therefore, our expression is 21-9z.
Now you know how to use the distributive property! Have a wonderful day! :D
Answer:
24 + 28
2*2*2*3 + 2*2*7 [prime factors]
You may distribute any common ones, for example:
4(6+7) [that is, 2*2*(2*3 + 7)
2(12+14)
Step-by-step explanation: