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3 years ago

15

Oscar ran the 100-yard dash in 12.41 seconds. Jesiah ran the 100-yard dash in 11.85 seconds. How many seconds faster was jesiah'

s time than oscar's time

1 answer:

julia-pushkina [17]3 years ago

5 0

Ok to find the difference, you have to subtract. 12.41-11.85=0.56. It was 0.56s faster.

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_2. You have a part-time job 4 days per week, 5 hours per day. How many hours will you work in two weeks?

marta [7]

Answer:

C) 40

Step-by-step explanation:

For every one day your work is 5 hours.

1 day = 5 hours

Set up a proportion so it would be:

$\frac{1 day}{5 hours} = \frac{4 days}{x hours}$

4 days x 5 hours = 20 hours/week

So now you know you know you work 20 hours/week, then multiply by 2 since they're asking how many hours will you work in two weeks:

20 hours x 2 weeks = 40 hours in two weeks

6 0

3 years ago

Solve the following equation: -2|3-4x|=10x

max2010maxim [7]

Answer:

I have to get the answer above hope it helps

5 0

3 years ago

Which is the equation of a line with a slope of -1/3 and a y-intercept at (0,1)?

Nutka1998 [239]

Answer:

The answer is

$\huge \boxed{y = - \frac{1}{3}x + 1 }$

Step-by-step explanation:

To find an equation of a line given the slope and a point we use the formula

$y - y_1 = m(x - x_1)$

where

m is the slope

( x1 , y1) is the point

From the question the point is (0,1) and slope - 1/3

The equation is

$y - 1 = - \frac{1}{3}(x - 0) \\ y - 1 = - \frac{1}{3} x$

We have the final answer as

$y = - \frac{1}{3} x + 1 \\$

Hope this helps you

4 0

3 years ago

Read 2 more answers

Evaluate b^2 c^-1 for b = -4 and c = 2.

Burka [1]

Answer:

8

Step-by-step explanation:

b^2 c^-1

Let b=-4 and c =2

(-4)^2 * (2)^-1

The negative exponent means it is in the denominator

(-4)^2 / (2)^1

16/2

8

4 0

4 years ago

Nathaniel left Los Angeles on the interstate, driving east towards Albuquerque at a speed of 48 miles per hour. Half an hour lat

elena-14-01-66 [18.8K]

Step 1

Nathaniel

Start time = t

Speed = 48

$\text{Distance = 48t}$

Step 2

Mikaela

$\begin{gathered} \text{Start time = t - 0.5} \\ \text{Speed = 72} \\ \text{Distance = 72(t - 0.5)} \end{gathered}$

Step 3

Equate the two distance

$\begin{gathered} 48t\text{ = 72(t - 0.5)} \\ 48t\text{ = 72t - 36} \\ 36\text{ = 72t - 48 t} \\ \text{36 = 24t} \\ \text{t = }\frac{36}{24} \\ \text{t = }\frac{3}{2}\text{ = 1}\frac{1}{2}\text{ hours} \end{gathered}$

Final answer

$It\text{ take( 1}\frac{1}{2}-\frac{1}{2})=1\text{ hours to catch up}$

Answer: 1 hour

8 0

1 year ago