Answer:
a^2-b^2=(a+b)(a-b) where a=4x and b=5. (4x+5)(4x-5)
Step-by-step explanation:
Since both terms are perfect squares,factor using the difference of squares formula
The speed of one bicyclist was 14.5mph, speed of the other bicyclist was 17.5mph.
Let the speed of one bicyclist=x mph
Let the speed of the other bicyclist=(x+3) mph
Hence:
Speed of one bicyclist:
3x+3(x+3)+2=98
3x+3x+9+2=98
6x=87
Divide both side by 6x
x=87/6
x=14.5 mph
Speed of the other bicyclist:
x+3 mph
14.5 mph+3 mph
=17.5 mph
Inconclusion the speed of one bicyclist was 14.5mph, speed of the other bicyclist was 17.5mph.
Learn more here:
brainly.com/question/18839894
V=1/3*πr² *h,
raduus r=32/2=16
V=1/3*3.14*(16)² *18=6*3.14*(16)² =4823.04
Answer:
A
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given expression is:
![(\sqrt[8]{x^7} )^{6}](https://tex.z-dn.net/?f=%28%5Csqrt%5B8%5D%7Bx%5E7%7D%20%29%5E%7B6%7D)
First we will use the rule:
![\sqrt[n]{x} = x^{\frac{1}{n} }](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%20%3D%20x%5E%7B%5Cfrac%7B1%7D%7Bn%7D%20%7D)
So for the given expression:
![\sqrt[8]{x^{7}}=(x^{7} )^{\frac{1}{8} }](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7Bx%5E%7B7%7D%7D%3D%28x%5E%7B7%7D%20%29%5E%7B%5Cfrac%7B1%7D%7B8%7D%20%7D)
We will use tha property of multiplication on powers:
Applying the outer exponent now
