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Serggg [28]
3 years ago
9

The wait times in line at a grocery store are roughly distributed normally with an average wait time of 7.6 minutes and a standa

rd deviation of 30 seconds. What is the probability that the wait time is between 6 and 7.3 minutes
Mathematics
1 answer:
Sati [7]3 years ago
5 0

Answer:

the probability that the wait time is between 6 and 7.3 minutes = 0.725

Step-by-step explanation:

Given -

Average wait time  (\nu)  =  7.6 minutes

Standard deviation (\sigma) = 30 second = .5 minute

Let X be the wait times in line at a grocery store

the probability that the wait time is between 6 and 7.3 minutes

[ Put z = \frac{X - \nu }{\sigma} ]

P (7.3> X>6  ) = P (\frac{7.3 - 7.6}{.5}> Z>\frac{6 - 7.6 }{.5} )

                         = (.6> Z> -3.2 )

[Using z table]

                         = Area to the left of z = .6 - area to the left of z = -.32

                         = .7257 - .0007 = 0.725

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harkovskaia [24]

Answer:

Row 1 = 2 white flowers

Row 2 = 3 white flowers

Row 3 = 4 white flowers

Step-by-step explanation:

Instead of having 1.5 times as many pink flowers as white flowers, Molly has decided to plant a garden with twice as many pink flowers as white flowers per row. If she plants 3 rows, with 4, 6, and 8 pink flowers, how can you find the number of white flowers in each of those rows?

Let

White flowers = x

Pink flowers = 2x

Molly plants 3 rows with 4, 6 and 8 pink flowers

Number of white flowers in each row is

Row 1

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2x = 4

Divide both sides by 2

x= 2

White flowers = 2 in row 1

Row 2

Pink flowers = 6

2x=6

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x= 3

White flowers in row 2 = 3

Row 3

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2x=8

Divide both sides by 2

x= 4

White flowers in row 3 = 4

Therefore, the number of white flowers in each rows are 2, 3 and 4 respectively

4 0
3 years ago
Read 2 more answers
A school debate team has 4 girls and 6 boys. A total of 3 of the team members will be chosen to participate in the district deba
mariarad [96]
There are 4+6=10 people in the team.
First calculate in how many ways you can choose 3 people from a group of 10 people, using combination:
(^{10} _3)=\frac{10!}{3!(10-3)!}=\frac{10!}{3! \times 7!}=\frac{7! \times 8 \times 9 \times 10}{6 \times 7!}=\frac{8 \times 9 \times 10}{6}=\frac{720}{6}=120
You can choose 3 people in 120 ways.

You can select 1 girl from a group of 4 girls in 4 ways.
Calculate in how many ways you can choose 2 boys from a group of 6 boys:
(^6 _2)=\frac{6!}{2! (6-2)!}=\frac{6!}{2! \times 4!}=\frac{4! \times 5 \times 6}{2 \times 4!}=\frac{5 \times 6}{2}=\frac{30}{2}=15
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Using the rule of product, you can calculate that you can choose 1 girl and 2 boys in 4×15=60 ways.

The probability of choosing 1 girl and 2 boys is the number of ways you can choose 1 girl and 2 boys divided by the number of ways you can choose 3 people from the group.
 P=\frac{60}{120}=\frac{1}{2}=50\%

The probability is 1/2, or 50%.
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3 years ago
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Vinvika [58]

Answer:

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Step-by-step explanation:

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3 years ago
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explanation:
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2 years ago
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0.04

Step-by-step explanation:

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3 years ago
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