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Mashutka [201]
2 years ago
7

Simplify 15y^-7/18y^-3 Assume y≠0

Mathematics
2 answers:
weeeeeb [17]2 years ago
6 0
The first step for simplifying the above fraction is to divide the terms with the same base by subtracting their exponents. 
\frac{15}{18y^{-3-(-7)} }
Remember that when there is a "-" sign in front of the parenthesis,, we need to change the sign of each term in the parenthesis. This changes the fraction to the following:
\frac{15}{18y^{-3+7 } }
Calculate the sum of the exponents.
\frac{15}{18 y^{4} }
Lastly,, reduce the fraction with 3 to find your final answer.
\frac{5}{6 y^{4} }
Let me know if you have any further questions.
:)
cupoosta [38]2 years ago
3 0

it's B, I got it on edgenuit y

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Maya Frankie invested $125,000 in the Washington Robinson Mutual Fund (Type B). The net asset of the fund at the time of purchas
vodomira [7]
Given:
125,000 investment
net asset of the fund was $21.29 back loaded with a loading rate of 3.9%

125,000/21.29 = 5,871.30 shares.

Maya Frankie bought 5,871.30 shares of the Washington Robinson Mutual Fund (Type B.)

The 3.9% loading rate will only be applicable once Maya decides to sell her shares. This is what back loaded means.
8 0
3 years ago
Which sequence of transformations confirms congruence by mapping shape I onto shape II?
Lubov Fominskaja [6]

Answer:

  • Neither of the choices is correct.

Explanation:

<u>1. Coordinates of the vertices of the figure I (preimage):</u>

  • (10, - 5)
  • (15, -5)
  • (10, - 10)
  • (15, -10)

<u />

<u>2. Coordinates of the vertices of the figure II (image):</u>

  • (0,10)
  • (0,15)
  • (-5,10)
  • (-5, 15)

Since many different rigid transformations can map the figure I into the figue II, you will need to use trial and error.

The most important is to do it in an educated way.

I will start by eliminating some options.

The first option, a reflection across the x-axis and 15 units left, does not work, because the reflection across the x-axis would shift the figure to a lower position than what you need.

The third option, a 90º counterclokwise rotation about the origin then a translation 10 units up, would move the figure to the second quadrant, and we need it in the third quadrant.

I will try now with the second choice, a 90º clockwise rotation and then 25 units up:

First, a 90º clockwise rotation, which is the same that a 270º counterclockwise rotation, follows the rule (x, y) → (y, -x)

Then, that results in:

  • (10, - 5) → (-5, -10)
  • (15, -5) → (-5, -15)
  • (10, - 10) → (-10, -10)
  • (15, -10) → (-10, -15)

Now, you can see that shifting 25 units up will not work, because you need that two x-coordinates become 0 (zero). So, this is not the correct set of transformations either.

A 180º rotation about the origin and a translation 10 units right follow this chain of rules:

  • (x, y) → (-x, -y) → (-x + 10, -y)

That means:

  • (10, - 5) → (-10,5) → (-10 + 10, 5) = (0, 5)
  • (15, -5) → (-15, 5) → (-15 + 10, 5) = (-5, 5)
  • (10, - 10) → (-10, 10) → (-10 + 10, 10) = (0, 10)
  • (15, -10) → (-15, 10) → (-15 + 10, 10) = (-5, 10)

        These last points do not coincide either with the vertices of the figure II.

In conclusion, neither of the choices gives the correct answer to the question.

8 0
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19.75-6.4=13.35
now 13.35-4.36=8.99
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Which of the following describes the roots of the polynomial function f(x) = (x-3)^4(x+6)^2
erma4kov [3.2K]

write out every grouping

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and multiply

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jeka57 [31]

Answer

g^-1(x)=\frac{8}{3}x-\frac{128}{3}

Step-by-step explanation:

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