Answer: Be Te Dubs meaning BTW Go To TigerAlgebra.com for questions like yours its really great
Step-by-step explanation:
|3x+6|<12
One solution was found :
-6 < x < 2
Absolute Value Inequality entered :
|3x+6|<12
Step by step solution :
Step 1 :
Rearrange this Absolute Value Inequality
Absolute value inequalitiy entered
|3x+6| < 12
Step 2 :
Clear the Absolute Value Bars
Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.
The Absolute Value term is |3x+6|
For the Negative case we'll use -(3x+6)
For the Positive case we'll use (3x+6)
Step 3 :
Solve the Negative Case
-(3x+6) < 12
Multiply
-3x-6 < 12
Rearrange and Add up
-3x < 18
Divide both sides by 3
-x < 6
Multiply both sides by (-1)
Remember to flip the inequality sign
x > -6
Which is the solution for the Negative Case
Step 4 :
Solve the Positive Case
(3x+6) < 12
Rearrange and Add up
3x < 6
Divide both sides by 3
x < 2
Which is the solution for the Positive Case
Step 5 :
Wrap up the solution
-6 < x < 2
Solution in Interval Notation
(-6,2)
Solution on the Number Line
One solution was found :
-6 < x < 2
Answer:
Step-by-step explanation:
Answer:
RTA= (x-2)·(x-11/2)/(x-2)(x-4)= (you can simplify again if you want by eliminating both (x-2)
(x-11/2)/(x-4)
Step-by-step explanation:
Ok we need to simplify the expression so:
x^2+3x-10= Bhaskara formula=
-3(±√9-4·1·(-10))/2·1=
X1=(-3+7/2)--> X1=2(R)---> (X-R)--->X-2
X2=(-3-7)/2 --> X2=11/2(R)---> (X-R)--->X-11/2
x^2-6x+8= Bhaskara formula=
6(±√36-4·1·8)/2·1=
X1=(6-2)/2=2--> X1=2(R)---> (X-R)--->X-2
X2=(6+2)/2=2--> X2=4(R)---> (X-R)--->X-4
so, The simplify expression is
(x-2)·(x-11/2)/(x-2)(x-4)=
The answer to the question above is 2.4
Answer:
50
Step-by-step explanation:
The total is 200 and 25% are juniors so u multiply 200 by 25%
Hope this helps
Correct me if this is wrong
