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wlad13 [49]
3 years ago
11

1. Which term below could not be part of a polynomial expression?

Mathematics
1 answer:
hichkok12 [17]3 years ago
8 0
I think it’s either 13 or 4x
You might be interested in
If 6 pens cost $2.40 What is the cost of 9 pens?
Shkiper50 [21]

Answer:

3.60$

Step-by-step explanation:

if we bought 3 pens that would equal 1.20$ so we add 1.20$ to 2.40$ we get 3.60$

3 0
3 years ago
Radical functions. please help me!
Sphinxa [80]
These are 8 questions and 8 answers:

1) Quesion 1:

 9+√2
---------
 4 - √7

Answer: the third option:

36 + 9√7 + 4√2 + √14
-----------------------------
               9

Explanation:

Multiply both numerator and denominator by the conjugate of the denominator.

The conjugate of 4 - √7 = 4 + √7

=>

\frac{9+ \sqrt{2} }{4- \sqrt{7} } . \frac{4+ \sqrt{7} }{4+ \sqrt{7} } =  \frac{(9)(4)+9 \sqrt{7}+4 \sqrt{2} + \sqrt{2} . \sqrt{7}  }{(4)^2-( \sqrt{7})^2 } =

= \frac{36+9 \sqrt{7} +4 \sqrt{2} + \sqrt{14} }{16-7}

2) Question 2: sum

5x (\sqrt[3]{x^2y})+2( \sqrt[3]{x^5y})

Answer: fourth option

7x( \sqrt[3]{x^2y} )

Explanation:

Take x^5 out of the second radical which will result in a like term of the first radical:

5x( \sqrt[3]{x^2y} )+2( \sqrt[3]{x^5y}) =5x( \sqrt[3]{x^2y} )+2x( \sqrt[3]{x^2y})=7x( \sqrt[3]{x^2y})

which is the fourth option

3) Question 3. Which expression is equivalent to:

\frac{ \sqrt{10} }{ \sqrt[4]{8} }

Answer: the first option

Explanation

\frac{ \sqrt{10} }{ \sqrt[4]{8} } = \frac{ \sqrt[4]{10^2} }{ \sqrt[4]{8} } = \frac{ \sqrt[4]{100} }{ \sqrt[4]{8} } .  \frac{ \sqrt[4]{8^3} }{ \sqrt[4]{8^3} }  = \frac{ \sqrt[4]{(100)(512)} }{8} = \frac{ \sqrt[4]{51200} }{8} = \frac{4 \sqrt[4]{200} }{8} = \frac{ \sqrt[4]{200} }{2}

4) Question 4 What is the simplest form?

Answer: the second option

Explanation:

\sqrt[4]{81x^8y^5}=x^2 y\sqrt[4]{3^4y}  =3x^2y \sqrt[4]{y}

5) Question 5 Product

Answer: the fourth option:

104x^4+16x^4 \sqrt{30} [/tex]\\Explanation:\\Use the square of a binomial product: (a + b)^2 = a^2 + 2ab + b^2\\[tex](4x \sqrt{5x^2} )^2+2(4x \sqrt{5x^2})(2x^2 \sqrt{6}) +(2x^2 \sqrt{6} )^2=

=16x^2(5x^2)+16x^4( \sqrt{30} )+4x^4(6)=80x^4+16x^4  \sqrt{30} +24x^4=

=104x^4+16x^4 \sqrt{30}

which is the fourth option.

6) Question 6 Product

Answer: fourth option

Explanation:

\sqrt[3]{16x^7} . \sqrt[3]{12x^9} = \sqrt[3]{2^4.2^2.3x^7x^9} =  \sqrt[3]{2^6.3.x^{16}}=2^2 x^5 \sqrt[3]{3x} =4 x^5\sqrt[3]{3x}

which is the fourth option.

7) Question 7. Simplified form of 2√18 + 3√2 + √162

Answer: 18√2

Explanation:

2 \sqrt{18}+3 \sqrt{2} + \sqrt{162}=2(3) \sqrt{2}  + 3 \sqrt{2} +9 \sqrt{2} =18 \sqrt{2}

which is the second option.

8) Question 8 which function is undefined for x = 0.

Answer: second option y = √ (x - 2)

Explanation.

The square root function is not defined for negative values.

When x = 0, x - 2 = -2, whose square root is not defined.

Therefore, the square root of x - 2 is not defined for x = 0.
5 0
3 years ago
Solve -17 + n over 3 = 33
ehidna [41]

Answer:

n=82

Step-by-step explanation:

\frac{17 + n}{3} = 33 \:  \:  \:  \frac{17 + n}{3} =  \frac{33}{1} \:  \:  \: 17 + n = 99 \:  \: \:  n = 99 - 17 \:  \:  \: n = 82

Proof:

17+n/3=33

17+82/3=33

99/3=33

33=33

Hope this helps ;) ❤❤❤

8 0
3 years ago
PLEASE HURRY! (And only respond if you know the answer please.)
Novosadov [1.4K]

Answer:

Step-by-step explanation:

If the no of standard version downloads = 230

Then higher version is twice than that = 460

Total = 2.1 x 230 + 4.9 x 460 = 2737

3 0
3 years ago
Need help pleaseI was bad at math in school so lwant to learn
aleksklad [387]

The probability of an event is expressed as

Pr(\text{event) =}\frac{Total\text{ number of favourable/desired outcome}}{Tota\text{l number of possible outcome}}

Given:

\begin{gathered} \text{Red}\Rightarrow2 \\ \text{Green}\Rightarrow3 \\ \text{Blue}\Rightarrow2 \\ \Rightarrow Total\text{ number of balls = 2+3+2=7 balls} \end{gathered}

The probability of drwing two blue balls one after the other is expressed as

Pr(\text{blue)}\times Pr(blue)

For the first draw:

\begin{gathered} Pr(\text{blue) = }\frac{number\text{ of blue balls}}{total\text{ number of balls}} \\ =\frac{2}{7} \end{gathered}

For the second draw, we have only 1 blue ball left out of a total of 6 balls (since a blue ball with drawn earlier).

Thus,

\begin{gathered} Pr(\text{blue)}=\frac{number\text{ of blue balls left}}{total\text{ number of balls left}} \\ =\frac{1}{6} \end{gathered}

The probability of drawing two blue balls one after the other is evaluted as

\begin{gathered} \frac{1}{6}\times\frac{2}{7} \\ =\frac{1}{21} \end{gathered}

The probablity that none of the balls drawn is blue is evaluted as

\begin{gathered} 1-\frac{1}{21} \\ =\frac{20}{21} \end{gathered}

Hence, the probablity that none of the balls drawn is blue is evaluted as

\frac{20}{21}

8 0
1 year ago
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