I will do 2 and 5 but I want you succeed so do the rest alone ok
2 is 13
5 is 2y I think good luck
Answer:
2
Step-by-step explanation:
For a quadratic function the average rate of change on an interval is the rate of change at the midpoint of the interval. The rate of change of a function is given by its derivative.
The derivative of f(x) = x^2 is f'(x) = 2x. The midpoint of the interval is (4+(-2))/2 = 1. Then the average rate of change is ...
f'(1) = 2(1) = 2
The average rate of change of f(x) on [-2, 4] is 2.
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<em>Alternate solution</em>
The average rate of change is the slope of the line between the end points of the interval:
m = (y2 -y1)/(x2 -x1)
m = (f(4) -f(-2))/(4 -(-2)) = (20 -8)/(6) = 2
The average rate of change on [-2, 4] is 2.
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The attached graph shows the points on the curve and a line with slope 2 between them. It also shows the various slope calculations.
Denominator is the number which appears at the
bottom of fraction so the fraction we want is in the form X/8 and also less
than 5/6
Lets start from changing the values of X from
1.
1/8 = 0.125 and 5/6 = 0.8333
2/8 = 0.25
3/8 = 0.375
4/8 = 0.5
5/8 = 0.625
6/8 = 0.75
7/8 = 0.875, this is greater than 5/6
<span>So, the fractions with denominator 8 and less
than 5/6 are 1/8, 2/8, 3/8, 4/8, 5/8 and 6/8</span>
Answer:
140
Step-by-step explanation:
yes
First your going to use commutative property to reorder the terms , so it would be
5x^4-x-35x^3+7 , then your going to factor out x & -7 from the equation once you factor that out you should have x(5x^3-1)-7(5x^3-1) after you got that your going to factor out 5x^3-2 and get the answer (x-7)(5x^3-1) which is your final answer.