Wait it says ur in high school so u can't be over 30. that isn't possible. So what's the problem here? not good at math.
Answer:
Step-by-step explanation:
From the given information:
the mean 
= 2300
Standard deviation = 
Standard deviation (SD) = 214.4761
TO find:
a) 



From the Z-table, since 5.595 is > 3.999

P(x > 3500) = 0.0001
b)
Here, the replacement time for the mean 
= 0.25
Replacement time for the Standard deviation 

For 115 component, the mean time = (115 × 20)+(114×0.25)
= 2300 + 28.5
= 2328.5
Standard deviation = 
= 
= 
= 
= 
= 214.482
Now; the required probability:




From the Z-table, since 8.376 is > 3.999
P(x > 4125) = 1 - 0.9999
P(x > 4125) = 0.0001