Answer:
Step-by-step explanation:
The desired formula parameters for Newton's Law of Cooling can be found from the given data. Then the completed formula can be used to find the temperature at the specified time.
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<h3>Given:</h3>

<h3>Find:</h3>
k
T(4)
<h3>Solution:</h3>
Filling in the given numbers, we have ...
185 = 68 +(208 -68)e^(-k·3)
117/140 = e^(-3k) . . . . . subtract 68, divide by 140
ln(117/140) = -3k . . . . . . take natural logarithms
k = ln(117/140)/-3 ≈ 0.060
__
The temperature after 4 minutes is about ...
T(4) = 68 +140e^(-0.060·4) ≈ 68 +140·0.787186
T(4) ≈ 178.205
After 4 minutes, the final temperature is about 178 °F.
Answer:
7 oof
Step-by-step explanation:
Answer:
2.
x³+2x²+5x+10
x²(x+2)+5(x+2)
taking common
(x+2)(x²+5) is your answer
a³-a²b²-ab+b³
taking common
a²(a-b²)-b(a-b²)
taking common
(a-b²)(a²-b)
NPr = n! / (n-r)!
8P4 = 8! / (8-4)!
= 8! / 4!
= 1,680
From the diagram, we know that it is an angle that adds up to 360
So
x+4x+2x+10+5x+50=360
Gather like terms
12x+60=360
Move sixty to the other side as a negative number
12x=300
Divide both sirs by twelve
x is equal to 25
AOB is 2x+10
Sub x in 2*25+10
AOB is 60
BOC is 5x+50
5*25+50, which is 175
BOD is x+2x+10
Which is 3x+10
Sub x
3*25+10 which is 85
:)