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zhannawk [14.2K]
3 years ago
13

Percent increase in the price

Mathematics
1 answer:
faust18 [17]3 years ago
3 0

Answer:

?

Step-by-step explanation:

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The graph of a line passes through the points (0, -2) and (6, 0). What is the equation of the line?
ra1l [238]

Answer:

y=0.3x-2

Step-by-step explanation:

first find the gradient

m=y2-y1/x2-x1

m=0-(-2)/6-0

m=0.3

then use this equation

y-y1=m(x-x1)

y-(-2)=0.3(x-0)

y+2=0.3x-0

y=0.3x-2

4 0
3 years ago
Invasive species often experience exponential population growth when introduced into a new environment. Zebra mussels are an inv
Oliga [24]

Answer:

If ‘a’ is the initial population of the Zebra mussels, then every six months, the population of Zebra mussels quadruples, i.e. it becomes 4a. In t years, i.e. in 2t intervals of 6 months each, the population of Zebra mussels can be computed with the help of a geometric series a, ar, ar2, ar3, …. arn-1 ( the series being finite with n terms) where a is the 1st term , r is the common ratio and n is the number of terms in the series..

Here, in 2t years, there will be 2t + 1 terms in the geometric series including the initial term. Thus in the above series, a = 10, r = 4 and n = 2t + 1. Then the population of the Zebra mussels after 2t years is the (2t +1)st term of the geometric series I.e. 10* ( 42t)                  

In 15 months, t = 15/12 = 1.25. Then the population of Zebra mussels after 15 months will be 10*(42.5 ) = 10 * 25 = 320

If after t years, the population of the Zebra mussels become 1 million , then we have

1000000 = 10 * (42t) or, 100000= 42t or,105 = 42t    Taking logarithms of both sides, we have 5 log 10 = 2t log 4 or, t = (5log10)/(2log4) = 5/1.20 years or (5/1.20) * 12 months = 50 months, i.e. 4 years and 2 months.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What are all the powers if 4 that range from 4 through 1000
LekaFEV [45]
You're just going to take exponents of 4. For example, 4 to the power of 1, 4 to the power of 2, 4 to the power of 3, and so on. To get the powers of 4, just multiply 4 by how much the exponent reads. For example 4 to the power of 3 is just 4 multiplied by itself 3 times.
4^1=4
4^2=16
4^3=64
4^4=256
4^5=1024
However, 1024 is greater than 1000 so we do not include it.
7 0
3 years ago
Where do the graphs of the linear equation y=2x+5 and y=-2x-3 intersect?
Aleksandr [31]
It graphs in the y=2x-3 so I say it’s d bc it is in the answer up above
6 0
3 years ago
Calculus 2
FinnZ [79.3K]

Answer:

See Below.

Step-by-step explanation:

We want to estimate the definite integral:

\displaystyle \int_1^47\sqrt{\ln(x)}\, dx

Using the Trapezoidal Rule, Midpoint Rule, and Simpson's Rule with six equal subdivisions.

1)

The trapezoidal rule is given by:

\displaystyle \int_{a}^bf(x)\, dx\approx\frac{\Delta x}{2}\Big(f(x_0)+2f(x_1)+...+2f(x_{n-1})+f(x_n)\Big)

Our limits of integration are from x = 1 to x = 4. With six equal subdivisions, each subdivision will measure:

\displaystyle \Delta x=\frac{4-1}{6}=\frac{1}{2}

Therefore, the trapezoidal approximation is:

\displaystyle =\frac{1/2}{2}\Big(f(1)+2f(1.5)+2f(2)+2f(2.5)+2f(3)+2f(3.5)+2f(4)\Big)

Evaluate:

\displaystyle =\frac{1}{4}(7)(\sqrt{\ln(1)}+2\sqrt{\ln(1.5)}+...+2\sqrt{\ln(3.5)}+\sqrt{\ln(4)})\\\\\approx18.139337

2)

The midpoint rule is given by:

\displaystyle \int_a^bf(x)\, dx\approx\sum_{i=1}^nf\Big(\frac{x_{i-1}+x_i}{2}\Big)\Delta x

Thus:

\displaystyle =\frac{1}{2}\Big(f\Big(\frac{1+1.5}{2}\Big)+f\Big(\frac{1.5+2}{2}\Big)+...+f\Big(\frac{3+3.5}{2}\Big)+f\Big(\frac{3.5+4}{2}\Big)\Big)

Simplify:

\displaystyle =\frac{1}{2}(7)\Big(f(1.25)+f(1.75)+...+f(3.25)+f(3.75)\Big)\\\\ =\frac{1}{2}(7) (\sqrt{\ln(1.25)}+\sqrt{\ln(1.75)}+...+\sqrt{\ln(3.25)}+\sqrt{\ln(3.75)})\\\\\approx 18.767319

3)

Simpson's Rule is given by:

\displaystyle \int_a^b f(x)\, dx\approx\frac{\Delta x}{3}\Big(f(x_0)+4f(x_1)+2f(x_2)+4f(x_3)+...+4f(x_{n-1})+f(x_n)\Big)

So:

\displaystyle =\frac{1/2}{3}\Big((f(1)+4f(1.5)+2f(2)+4f(2.5)+...+4f(3.5)+f(4)\Big)

Simplify:

\displaystyle =\frac{1}{6}(7)(\sqrt{\ln(1)}+4\sqrt{\ln(1.5)}+2\sqrt{\ln(2)}+4\sqrt{\ln(2.5)}+...+4\sqrt{\ln(3.5)}+\sqrt{\ln(4)})\\\\\approx 18.423834

6 0
3 years ago
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