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3 years ago

Percent increase in the price

Mathematics

1 answer:

faust18 [17]3 years ago

3 0

Answer:

Step-by-step explanation:

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NEED HELP!!!!!!!!!!!!!!!

musickatia [10]

It's D, it's the only one where it has a -6 at the end other than A, but if you look at the A when distributed there isn't a 23x<span />

3 0

3 years ago

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If Y varies directly with X solve the following :

BARSIC [14]

Answer:

a) x = -270

b) y = 304/9 or y = 33.78

c) x = -37.8

Step-by-step explanation:

y varies directly with x so y = kx

y = kx

k = y/x

k = 10/-30 = -1/3

y = -1/3 x

If y = 90 then

90 = -1/3 x

x = 90 *(-3) = -270

k = y/x

k = -19/-4.5

k = 38/9

y = 38/9 x

If x = - 8 then

y = 38/9 *(-8)

y = 304/9 or y = 33.78

k = y/x

k = -4.3 / 12.9

k = - 1/3

y = -1/3 x

If y = 12.6 then

12.6 = -1/3 x

x = 12.6 *(-3)

x = -37.8

5 0

3 years ago

What are the zeros of f(x)=(x+5)(x-9)?

klemol [59]

Answer:

x= -5

x= 9

Step-by-step explanation:

5 0

2 years ago

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1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera

Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

$SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}$

$SP \approx 8.246$

$PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}$

$PA \approx 8.246$

$AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}$

$AZ \approx 8.246$

$ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}$

$ZS \approx 8.246$

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

$m_{SA} = \frac{6-(-4)}{6-(-4)}$

$m_{SA} = 1$

$m_{PZ} = \frac{4-(-2)}{-2-4}$

$m_{PZ} = -1$

Since $m_{SA}\cdot m_{PZ} = -1$ , diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

$M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)$

$M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)$

$M_{SA} = (-2,-2)+(3,3)$

$M_{SA} = (1,1)$

$M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)$

$M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)$

$M_{PZ} = (2,-1)+(-1,2)$

$M_{PZ} = (1,1)$

Then, the diagonals SA and PZ bisect each other.

8 0

2 years ago

last month dory biked 11 times as many miles as karly. together they biked a total of 156 miles. how many miles did dory bike la

soldier1979 [14.2K]

I think You have to divide 159 by 11, and that would make you get 14.

7 0

3 years ago

Read 2 more answers