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lana [24]
3 years ago
9

NEED HELP!!!!!!!!!!!!!!!

Mathematics
2 answers:
madreJ [45]3 years ago
6 0

Answer:

Option D. -(4x-3)(5x-2)

Step-by-step explanation:

we have

f(x)=-20x^{2}+23x-6

Equate the function to zero

-20x^{2}+23x-6=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

-20x^{2}+23x=6

Factor the leading coefficient

-20(x^{2}-(23/20)x)=6

Complete the square. Remember to balance the equation by adding the same constants to each side

-20(x^{2}-(23/20)x+(529/1,600))=6-(529/80)

-20(x^{2}-(23/20)x+(529/1,600))=-(49/80)

(x^{2}-(23/20)x+(529/1,600))=(49/1,600)

Rewrite as perfect squares

(x-(23/40))^{2}=(49/1,600)

(x-(23/40))=(+/-)(7/40)

x=(23/40)(+/-)(7/40)

x=(23/40)(+)(7/40)=30/40=3/4

x=(23/40)(-)(7/40)=16/40=2/5

therefore

-20x^{2}+23x-6=-20(x-(3/4))(x-(2/5))

-20x^{2}+23x-6=-(5)(4)(x-(3/4))(x-(2/5))

-20x^{2}+23x-6=-(4x-3)(5x-2)

musickatia [10]3 years ago
3 0
It's D, it's the only one where it has a -6 at the end other than A, but if you look at the A when distributed there isn't a 23x<span />
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