Answer:
H=9;8)
B=(5;4) (ball)
R=(7;0) (hit point)
B'=symetric of B axis perpendicular of x in R
B'=(7+(7-5);4)=(9;4)
Equation BR: y-4=(0-4)/(7-5)(x-5)==>y=-2x+14
Equation RB': y-4=(4-0)/(9-7)(x-9)==>y=2x-14
Is H a point of RB'? y=2x-14 : 8=? 2*9-14==>8=?4 No!
you will not make your putt
Step-by-step explanation:
The classification would be a right triangle
Answer:
Step-by-step explanation:
84 = 2 * 2 *3 * 7
Answer:

Step-by-step explanation:

Add 6 to both sides:


Divide both sides by -3:


Subtract 4 from both sides:


Divide both sides by 2:


Answer:
The first graph.
Step-by-step explanation:
The equation is x is greater than 2. Therefore, the graph needs to shade anything greater than 2, but not 2.