You're given that φ is an angle that terminates in the third quadrant (III). This means that both cos(φ) and sin(φ), and thus sec(φ) and csc(φ), are negative.
Recall the Pythagorean identity,
cos²(φ) + sin²(φ) = 1
Multiply the equation uniformly by 1/cos²(φ),
cos²(φ)/cos²(φ) + sin²(φ)/cos²(φ) = 1/cos²(φ)
1 + tan²(φ) = sec²(φ)
Solve for sec(φ) :
sec(φ) = - √(1 + tan²(φ))
Given that cot(φ) = 1/4, we have tan(φ) = 1/cot(φ) = 1/(1/4) = 4. Then
sec(φ) = - √(1 + 4²) = -√17
Answer: (0,3)
Step-by-step explanation:
You follow the formulas to find the x and y of the dividing points.
Xp= x1+ a/a+b (x2-x1)
Xp= 10+5/5+3(-6-10)
Xp=10+5/8(-16)
Solve the problem above and you end up with “0” as your x.
Yp= y1+ a/a+b (y2-y1)
Yp= -2+ 5/8 (6+2)
Yp= -2+ 5/8 (8)
Solve this problem above and you end up with “3” as your y. Therefore, the point that divides the line segment between (10, -2) and (-6,6) into a ratio of 5:3 is (0, 3).
Answer:
3.260 is greater.
Step-by-step explanation:
The ones place is the same, the tenths place is the same, the hundredths place is different. 3.260 has a greater hundredths place, so 3.260 > 3.206
