Answer:
complementary
Step-by-step explanation:
Answer: the expected value of the sum of the rolls is 12.5
Step-by-step explanation:
Given that
Caleb has 4 sided die, 6 sided die and 12 sided die
first we calculate the expected number of each of the dice
so Expected number for 4 sided die will be;
E(X1)4-sided = ( (1+2+3+4) / 4 ) = 2.5
E(X2)6-sided = ( (1+2+3+4+5+6) / 6 ) = 3.5
E(X3)12-sided = ( (1+2+3+4+5+6+7+8+9+10+11+12) / 12 ) = 6.5
so, the expected value of the sum of the roll will be
E(X) = ( E(X1) + E(X2) + E(X3)
E(X) = 2.5 + 3.5 + 6.5
E(X) = 12.5
Therefore, the expected value of the sum of the rolls is 12.5
Answer:
a) k should be equal to 3/16 in order for f to be a density function.
b) The probability that the measurement of a random error is less than 1/2 is 0.7734
c) The probability that the magnitude of a random error is more than 0.8 is 0.164
Step-by-step explanation:
a) In order to find k we need to integrate f between -1 and 1 and equalize the result to 1, so that f is a density function.
16k/3 = 1
k = 3/16
b) For this probability we have to integrate f between -1 and 0.5 (since f takes the value 0 for lower values than -1)
c) For |x| to be greater than 0.8, either x>0.8 or x < -0.8. We should integrate f between 0.8 and 1, because we want values greater than 0.8, and f is 0 after 1; and between -1 and 0.8.
You are starting at 0 dollars and it increases by $60 per week. The rate of chance is $60 per week.
Answer:
Horizontal stretch by a factor of ½.
Step-by-step explanation:
We were given the parent function as:
This was transformed to:
Let
and
Then:
Hence the parent function has been stretched horizontally by a factor of 1/2 to obtain the transformed function.