What is the point-slope equation of the line that is perpendicular to the line shown and passes through (-4, -3)?

Mathematics

1 answer:

Juliette [100K]3 years ago

5 0

Answer:

y+3= -4x

Step-by-step explanation:

general equation is (y-y1) = m(x-x1)

m=rise/run= -4/1 (is negative because looking from left to right on the graph it goes downward)

pick any point on the line to put in. the equation for example (0,-3)

y+3= -4x

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Graph x2 = 4y and state the vertex, focus, axis of symmetry, and directrix.This is the same graphing that I've done in the past: y = (1/4)x2. So I'll do the graph as usual: The vertex is obviously at the origin, but I need to "show" this "algebraically" by rearranging the given equation into the conics form:x2 = 4y Copyright © Elizabeth Stapel 2010-2011 All Rights Reserved
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