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marishachu [46]
2 years ago
14

Helpppp me plz i dont get it

Mathematics
2 answers:
SOVA2 [1]2 years ago
6 0
Try 3.14x2= 6.28 im so sorry if its wrong
Alex Ar [27]2 years ago
6 0
360 I’m not to sure if it’s correct sorry
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Please help me! This math is killing me!
ankoles [38]

Answer:C

Step-by-step explanation:

8 0
2 years ago
Simplest form of (36^)1/3
nekit [7.7K]

3,301927249 = ³√36

As discussed in one of my videos on my channel [USERNAME: MATHEMATICS WIZARD] on the Six Rational Exponential Rules, this one states that with a numerator of 1 in the exponent, you take the multiplicative inverse [reciprocal] of the fraction, and set the whole number equal to the root, bringing your a inside the radical, which is 36.

ⁿ√aᵐ = aᵐ\ⁿ → works for both: numerator ≥ 1

I am joyous to assist you anytime.

5 0
2 years ago
What is the next number in the following pattern?<br> 4,- 6, 8,- 10, 12, ...
Scorpion4ik [409]

Answer:

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Step-by-step explanation:

im not really sure

7 0
2 years ago
Read 2 more answers
Rita is making a beaded bracelet. She has a collection of 160 blue beads, 80 gray beads, and 240 pink beads. What is the estimat
a_sh-v [17]

Step-by-step explanation:

Given that Rita is making a beaded bracelet. She has a collection of 160 blue beads, 80 gray beads, and 240 pink beads. We are to calculate the probability that Rita will need to pick atleast 5 beads before she picks a grey bead from her collection.

Prob for drawing atleast 5 beads before she picks a grey bead from her collection

= 1-Prob for drawing atleast one grey beed in the first 5 draws.

(Because these two are complementary events)

no of grey beeds drawn in first 5 trials is

Bi=(5,1/6)

Prob for drawing atleast one grey beed in the first 5 draws.

=1-Prob of no grey

Hence required prob=P(X=0 in first 5 draws)

= 0.4018

6th beeds onwards can be grey also.

Nearest answer is c)0.45

7 0
2 years ago
What is the product of -2x^3+x-5 and x^3-3x-4 ?
murzikaleks [220]
To find the product of <span>-2x^3+x-5 and x^3-3x-4, we need to multiply each term in the first polynomial by the second polynomial. (So, x^3 - 3x - 4) times ....
-2x^3 = -2x^6 + 6x^4 + 8x^3
x = x^4 - 3x^2 - 4x
-5 = -5x^3 + 15x + 20
If we add all these together, we get (-2x^6 + 7x^4 + 3x^3 - 3x^2 + 11x + 20)</span>
6 0
3 years ago
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