Answer:
Option 1 - Using the Subtraction Property of Equality, 2 is subtracted from both sides of the equation.
Step-by-step explanation:
Given : Process
Step 1: 4x + 2 = 10
Step 2: 4x = 8
To find : Which justification describes the process?
Solution :
From step 1 to step 2, we subtract 2 both sides
Step 1: 4x + 2 = 10
Subtracting 2 both side,
⇒ 4x + 2-2 = 10-2
Step 2: 4x = 8
So, The best justification is 'Using the Subtraction Property of Equality, 2 is subtracted from both sides of the equation'.
Therefore, Option 1 is correct.
Answer:
1. 40%
2. The theoretical probability is 3% greater than the experimental probability.
Step-by-step explanation:
We are informed that a number cube is rolled 20 times and the number 4 is rolled 8 times. The experimental probability of rolling a 4 is;
(the number of times a 4 was rolled)/(total number of rolls)
8/20 = 0.4
0.4*100 = 40%
The experimental probability of obtaining at least one tails, one or more tails, is represented in mathematical notation as;
P(HT or TH or TT)
The above events are mutually exclusive, thus;
P(HT or TH or TT) = P(HT) + P(TH) + P( TT)
= (22+34+16)/(28+22+34+16)
= 0.72 = 72%
On the other hand, the theoretical probability of obtaining at least one tails,
P(HT or TH or TT) = 3/4
= 75%
This is because there is at least one tail in 3 out of 4 possible outcomes.
Therefore, it is true to say that the theoretical probability is 3% greater than the experimental probability.
Answer:
D. about 8.5 mi
Step-by-step explanation:
To go from Aesha to Josh, you go 6 units right and 6 units up.
Each unit is a mile, so you go 6 miles right and 6 miles up.
Think of each 6 mile distance as a leg of a right triangle, and the direct distance from one place to the other as the hypotenuse of the right triangle. Use the Pythagorean theorem to find the length of the hypotenuse.
a^2 + b^2 = c^2
The 6-mile legs are a and b. c is the hypotenuse.
(6 mi)^2 + (6 mi)^2 = c^2
c^2 = 36 mi^2 + 36 mi^2
c^2 = 72 mi^2
c = sqrt(72) mi
c = sqrt(36 * 2) mi
c = 6sqrt(2) mi
c = 6(1.4142) mi
c = 8.5 mi
