So we gots apolynomial equation that is 3rd degree and crosses x axis at x=-1, x=0 and x=2
the factors of a poly equation that passes through r1,r2,r3 is
(x-r1)(x-r2)(x-r3)
so
r1=-1
r2=0
r3=2
f(x)=(x-(-1))(x-0)(x-2)
f(x)=(x+1)(x)(x-2)
f(x)=x³-x²-2x
leading coefient is posiitve because 3rd degree equations that are postive go bottom left to top right
yah
actually that looks like the exact graph
both
f(x)=(x+1)(x)(x-2)
and
f(x)=x³-x²-2x
are correct
82/4+20-15
82:4=20.5
20.5+20=40.5
40.5-15=25.5
Y intercept occurs when x = o so it is -2(0-3) + 4 = -2
x intercepts:-
-2(x - 3)^2 + 4 = 0
(x - 3)^2 = -4/-2 = 2
x - 3 = +/- sqrt2
x = 3 + sqrt2 and 3- sqrt2
1. Use the distributive property:
Then
2. Separate terms with m in left side and without m in right side:
This expression is false for all values of x, then the equation doesn't have solutions.
Answer: no solution
Answer:
3
Step-by-step explanation:
We want to cancel out the 3y. The second equation has a -y so if we multiply that by 3 we'll get -3y and when we add the ys go away.
