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Hitman42 [59]
3 years ago
13

easy car rental charges $40 a day plus $.25 per mile race. rent a car charges $25 a day plus $.45 per mile. what number of miles

results in the same cost for one day?
Mathematics
1 answer:
DiKsa [7]3 years ago
6 0
A: cost= 3*55+.35m
B: cost=3*50+.40m

set the costs equal, and solve for m.
You might be interested in
If the first of three consecutive integers is subtracted from 138, the result is the sum of the second and third. What are the i
Murljashka [212]

Answer:

<h2>45, 46, 47</h2>

Step-by-step explanation:

n, n + 1, n + 2 - three consecutive integers

The equation:

138 - n = (n + 1) + (n + 2)

138 - n = n + 1 + n + 2                 <em>combile like terms</em>

138 - n = 2n + 3           <em>subtract 138 from both sides</em>

-n = 2n - 135               <em>subtract 2n from both sides</em>

-3n = -135            <em>divide both sides by (-3)</em>

n = 45

n + 1 = 46

n + 2 = 47

6 0
4 years ago
F(x)=4(x+2)(x+2)-6 in standard form
ollegr [7]

Answer:

4x^2 + 4x -2

Step-by-step explanation:

Use FOIL to solve (x+2) (x+2)

4(x^2 + 4x +4) - 6

4x^2 + 4x -2

8 0
3 years ago
12) A candy company used 8 gallons of syrup to make 4 batches of candy. What is the rate of syrup per batch?
Black_prince [1.1K]
The answer is 2 gallons of syrup per batch.
3 0
3 years ago
Samples of 20 parts from a metal punching process are selected every hour. Typically, 1% of the parts require rework. Let X deno
Roman55 [17]

Answer:

a) P(X>np+3\sqrt{np(1-p)}=0.017

b) P(x>1)=0.190

c) P(Y>1)=0.651

Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

The variance is: Var(X) = np(1 − p) = 0.2 × 0.99 = 0.198,

The standard deviation SD(X)= \sqrt{0.198} ≈ 0.445

a) P(X>np+3\sqrt{np(1-p)}=P(X>0.2+3×0.445)=P(X>1.535)=P(X≥2)

Probability function is given by:

\frac{n!}{x!(n-x)!} *p^x*(1-p)^{(n-x)}

P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - \frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}-\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - \frac{20!}{0!(20-1)!} *(0.04)^{1}*(1-0.04)^{(20-1)} - \frac{20!}{0!(20-0)!} *(0.04)^{0}*(1-0.04)^{(20-0)}

P(x>1)= 1 - 0.368 - 0.442=0.190

c) In this case we consider p=0.19 (Probability that X exceeds 1)

In this experiment Y is the number of hours and n= 5 hours.

Then, we check the probability in each hour:

P(Y>1)=1- P(Y=0)

P(Y=0)=\frac{5!}{0!(5-0)!} *(0.19)^{0}*(1-0.19)^{(5-0)}=0.349

P(Y>1)=1-0.349=0.651

3 0
3 years ago
Find the sum of 2 and 3/2
poizon [28]

Answer:<u>3</u>

Step-by-step explanation:2+3/2=

3/2=1

2+1=3 Or  3.5

8 0
3 years ago
Read 2 more answers
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