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Ad libitum [116K]
4 years ago
6

PLEASE HELP FAST-----------Passes through the point (-2, 0) and is perpendicular to the line y=-9

Mathematics
1 answer:
miskamm [114]4 years ago
7 0

Answer:  x = -2

<u>Step-by-step explanation:</u>

A line perpendicular to y= (anything) is ....... x = ____

Since it must pass through a coordinate x = -2, y = 0

then the equation of the line is: x = -2

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Hi ansswer for this quick i will mark u as brainlest
andrew11 [14]

Answer:

Smallest B. 300,000

Larger C. 1,000,002

Largest A. 3,000,000

Step-by-step explanation:

A. 100 × 30,000

= 3,000,000

B. 3 × 100,000

= 300,000

C. 1 million + 2

= 1,000,000 + 2

= 1,000,002

Arrange from smallest to the largest

Smallest B. 300,000

Larger C. 1,000,002

Largest A. 3,000,000

7 0
3 years ago
Counting from 1 to 100, how many 6s will you encounter?
Basile [38]
6, 16, 26, 36, 46, 56, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 76, 86, 96 so 20 6's
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3 years ago
Factor completely.<br> 3h^4+24h^3+21h^2. BRAINLIST PLEASE HELP FAST!!!
mote1985 [20]
<span> 3h2 • (h + 7) • (h + 1) is the simplified version.</span>
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3 years ago
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strojnjashka [21]

Answer:

X^2+3X-10

Step-x^2by-step explanation:

8 0
3 years ago
Read 2 more answers
How do I solve these problems? ln(x) = 5.6 + ln(7.5) and log(x) = 5.6 - log(7.5)
SOVA2 [1]

Use the rules of logarithms and the rules of exponents.

... ln(ab) = ln(a) + ln(b)

... e^ln(a) = a

... (a^b)·(a^c) = a^(b+c)

_____

1) Use the second rule and take the antilog.

... e^ln(x) = x = e^(5.6 + ln(7.5))

... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents

... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms

... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)

2) Similar to the previous problem, except base-10 logs are involved.

... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.

... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5

... x ≈ 53,080.96

8 0
3 years ago
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