Answer:
a) 95% confidence interval estimate of the true weight is (3.026, 3.274)
b) 99% confidence interval estimate of the true weight is (2.944, 3.356)
Step-by-step explanation:
Confidence Interval can be calculated using M±ME where
- M is the mean of five successive weightings (3.150)
- ME is the margin of error from the mean
And margin of error (ME) can be calculated using the formula
ME=
where
- t is the corresponding statistic in the given confidence level and degrees of freedom(t-score)
- s is the standard deviation of the random error (0.1)
Using the numbers 95% confidence interval estimate of the true weight is:
3.150±
≈3.150±0.124
And 99% confidence interval estimate of the true weight is:
3.150±
≈3.150±0.206
Where is this at?
Could you send it in comments here or something?
the circle has a diameter of 12, thus its radius is half that, or 6.
![\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=6 \end{cases}\implies A=\pi 6^2\implies A=36\pi \\\\\\ A \approx 113.0973355\implies A=\stackrel{\textit{rounded up}}{113.1}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D6%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%206%5E2%5Cimplies%20A%3D36%5Cpi%20%5C%5C%5C%5C%5C%5C%20A%20%5Capprox%20113.0973355%5Cimplies%20A%3D%5Cstackrel%7B%5Ctextit%7Brounded%20up%7D%7D%7B113.1%7D)
Answer: 7 4/9
Step-by-step explanation:
Find least common denominator of 3 and 9, which is 9. So, 11 1/9 - 3 6/9 = 7 4/9