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DerKrebs [107]
3 years ago
6

Question 1

Mathematics
1 answer:
Vlad1618 [11]3 years ago
4 0

Answer:

1 . Segment EF is twice as as segment AB

4. The length of segment EH is 16 units

Step-by-step explanation:

Quadrilateral EFGH was created by increasing all the length segments of quadrilateral ABCD proportionally by multiplying the lengths of ABCD by a scale factor.

Scale factor used = GH/CD = 12/6 = 2

Let's examine each statements to see which is true or not true:

1 . "Segment EF is twice as as segment AB."

This is true. EF corresponds to AB. Since scale factor = 2, length of any segment of quadrilateral EFGH would be twice the length of quadrilateral ABCD.

2. "Segment CD is twice as long as segment FG."

This is not true, because segment CD does not correspond to segment FG. Segments in EFGH are twice as the corresponding segments in ABCD.

3. "The measure of angle HEF is twice the measure of the angle DAB."

This is not true. Shape remains the same. Only the size changes.

4. "The length of segment EH is 16 units".

This is true because EH is twice the corresponding segment in ABCD, which is 2"AD = 2*8 = 16 units.

5. "The area of EFGH is twice the are of ABCD"

This is not true. Area of the scaled copy would be times 4 of the original figure.

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What is the measure of f in the figure shown?
SCORPION-xisa [38]

Answer:

The measure of angle f is 61°

Step-by-step explanation:

A straight line is 180° meaning;

180 - 98 = 82

82 is the angle measure of the unlabeled angle.

All triangles angles add up to 180° meaning;

37 + 82 = 119

180 - 119 = 61°

5 0
3 years ago
Given the position of the particle, what the position(s) of the particle when it’s at rest
choli [55]

The position function of a particle is given by:

X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t

The velocity function is the derivative of the position:

\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}

The particle will be at rest when the velocity is 0, thus we solve the equation:

2t^2-9t-18=0

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Substituting:

\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}

We have two possible answers:

\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

undefined

6 0
1 year ago
Solving multistep linear equations and inequalities<br>help me please​
butalik [34]

Answer:

Step-by-step explanation:

Part A:

C = 10t + s

Part B:

10(3) + 8

30 + 8 = $38

5 0
3 years ago
Solve √(3x+7)+2√(x-8)=0.
laiz [17]

Answer:

The solution to this question is 39

Step-by-step explanation:

Given that :

√(3x+7)+2√(x-8)=0.    

√(3x+7)=-2√(x-8)           (i)

square of the equation (i)

Then

(√(3x+7))^2=(-2√(x-8))^2

we know that √a*√a=(√a)^2=a So,

(3x+7)=4(x-8)      

3x+7=4x-32        //multiply by 4

32+7=4x-3x  exchange the value.

39=1x

x=39.

4 0
3 years ago
2) In 1000 sq. meter of land a farmer cultivated 765 kg of rice with the wastage of 23.5%. I) Find the weight of the wastage. II
LiRa [457]

Answer:

Weight of wastage=179.775kg

weight of rice cultivated= 585.225 kg

percentage of rice cultivated=76.5%

Step-by-step explanation:

Area of land=100 square meters

Cultivated rice=765kg

Wastage=23.5%

1) Weight of the wastage=23.5% of 765kg

=23.5/100 × 765

=17977.5 / 100

=179.775 kg

2) Weight and percentage of rice cultivated.

weight of rice cultivated = 765 kg - 179. 775 kg

= 585.225 kg

percentage of rice cultivated = 100 - 23.5

= 76.5%

3) if area is increased 40 times in size

New area=1000 square meters × 40

=40,000 square meters

Cultivated rice= 765kg × 40

=30,600 kg

Cultivated rice excluding wastage=585.225 kg × 40

=23,409 kg

8 0
3 years ago
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