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DerKrebs [107]
3 years ago
6

Question 1

Mathematics
1 answer:
Vlad1618 [11]3 years ago
4 0

Answer:

1 . Segment EF is twice as as segment AB

4. The length of segment EH is 16 units

Step-by-step explanation:

Quadrilateral EFGH was created by increasing all the length segments of quadrilateral ABCD proportionally by multiplying the lengths of ABCD by a scale factor.

Scale factor used = GH/CD = 12/6 = 2

Let's examine each statements to see which is true or not true:

1 . "Segment EF is twice as as segment AB."

This is true. EF corresponds to AB. Since scale factor = 2, length of any segment of quadrilateral EFGH would be twice the length of quadrilateral ABCD.

2. "Segment CD is twice as long as segment FG."

This is not true, because segment CD does not correspond to segment FG. Segments in EFGH are twice as the corresponding segments in ABCD.

3. "The measure of angle HEF is twice the measure of the angle DAB."

This is not true. Shape remains the same. Only the size changes.

4. "The length of segment EH is 16 units".

This is true because EH is twice the corresponding segment in ABCD, which is 2"AD = 2*8 = 16 units.

5. "The area of EFGH is twice the are of ABCD"

This is not true. Area of the scaled copy would be times 4 of the original figure.

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Step-by-step explanation:

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3 years ago
What are the endpoint coordinates for the midsegment of △PQR that is parallel to PQ¯¯¯¯¯?
andriy [413]

Answer:

M(x₄ ,y₄) = (-3.5 , 0.5)  and

N (x₅ ,y₅) = ( -1 , -0.5 )

Step-by-step explanation:

Let the endpoint coordinates for the mid segment of △PQR that is parallel to PQ be

M(x₄ ,y₄) and N(x₅ ,y₅) such that MN || PQ

point P( x₁ , y₁) ≡ ( -3 ,3 )

point Q( x₂ , y₂) ≡ (2 , 1 )

point R( x₂ , y₂) ≡ (-4 , -2)  

To Find:

M(x₄ ,y₄) = ?  and

N (x₅ ,y₅) = ?

Solution:

We have Mid Point Formula as

Mid\ point(x,y)=(\frac{x_{1}+x_{2} }{2}, \frac{y_{1}+y_{2} }{2})

As M is the mid point of PR and N is the mid point of RQ so we will have

Mid\ pointM(x_{4} ,y_{4})=(\frac{x_{1}+x_{3} }{2}, \frac{y_{1}+y_{3} }{2})

Mid\ pointN(x_{5} ,y_{5})=(\frac{x_{2}+x_{3} }{2}, \frac{y_{2}+y_{3} }{2})

Substituting the given value in above equation we get

Mid\ pointM(x_{4} ,y_{4})=(\frac{-3+-4 }{2}, \frac{3+-2} }{2})

∴ Mid\ pointM(x_{4} ,y_{4})=(\frac{-7} }{2}, \frac{1}{2})

∴ Mid\ pointM(x_{4} ,y_{4})=(-3.5, 0.5)

Similarly,

Mid\ pointN(x_{5} ,y_{5})=(\frac{2+-4 }{2}, \frac{1+-2 }{2})

∴ Mid\ pointN(x_{5} ,y_{5})=(\frac{-2 }{2}, \frac{-1}{2})

∴ Mid\ pointN(x_{5} ,y_{5})=(-1, -0.5)

∴ M(x₄ ,y₄) = (-3.5 , 0.5)  and

  N (x₅ ,y₅) = ( -1 , -0.5 )

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myrzilka [38]

Answer:

I think its 28 feet

Step-by-step explanation:

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