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2 years ago

8th grade easy math pls help

Mathematics

1 answer:

sleet_krkn [62]2 years ago

4 0

Answer: Function 1 has the greater rate change

Step-by-step explanation:

This is how it looks like as a graph

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(y+3):(y+5)=k:1 show that y=(5k-3)/(1-k) hence y=(5k-2)/(1-k)

luda_lava [24]

hi,

Express the ratios in fractional form, that is

= ( cross- multiply )

y + 3 = k(y + 5) ← distribute

y + 3 = ky + 5k ( subtract ky from both sides )

y - ky + 3 = 5k ( subtract 3 from both sides )

y - ky = 5k - 3 ← factor out y from each term on the left side

y(1 - k) = 5k - 3 ← divide both sides by (1 - k)

y = 5k- 3

____

1 - k

4 0

3 years ago

Please help me with this it’s due soon

KonstantinChe [14]

Answer:

39.5 degrees

Step-by-step explanation:

180-101=79

79/2=39.5

3 0

3 years ago

Read 2 more answers

Please help with question 6

Kitty [74]

Answer:

y = -3x - 1

Use the methods on your other questions.

6 0

2 years ago

Liquid A has a density of 0.7g/cm^3

TiliK225 [7]

$\rho = \frac{m}{V} \Rightarrow V=\frac{m}{\rho}$
ρ - density, m - mass, V - volume

Liquid A:
$\rho=0.7 \ \frac{g}{cm^3} \\
m=140 \ g \\
\\ V=\frac{140 \ g}{0.7 \ \frac{g}{cm^3}}=200 \ cm^3$

Liquid B:
$\rho=1.6 \ \frac{g}{cm^3} \\
m=128 \ g \\
\\ V=\frac{128 \ g}{1.6 \ \frac{g}{cm^3}}=80 \ cm^3$

Liquid C:
$m=140 \ g + 128 \ g=268 \ g \\
V=200 \ cm^3 + 80 \ cm^3=280 \ cm^3 \\ \\
\rho=\frac{268 \ g}{280 \ cm^3} \approx 0.96 \ \frac{g}{cm^3}$

The density of liquid C is approximately 0.96 g/cm³.

5 0

3 years ago

Read 2 more answers

Is this right? please helpppp

erastova [34]

Si, estoy seguro de que tienes razón

6 0

3 years ago