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Stella [2.4K]
3 years ago
15

Correct answers only please!

Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
8 0

Answer:

a is the answer

Step-by-step explanation:

work is pictured and shown

sasho [114]3 years ago
3 0
The correct answer is A
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A block is 12 g and volume is 6 what is the density
WITCHER [35]

Answer: c.)2 g/ml is the correct answer.

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3 years ago
Is this equation a linear relation, and please solve the equation?<br> -3x + 2y = 1
Liono4ka [1.6K]

Answer:

Step-by-step explanation:

It is a linear equation and the gradient equation is given as:

y=mx+c

Where m is the gradient and c is the y intercept

-3x+2y=1

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Dividing all through by 2

y=1/2 + 3x/2

Therefore the gradient of this linear equation is 3/2 and the y intercept is 1/2

8 0
3 years ago
Find all possible values of k so that x^2 + kx - 32 can be factored.
daser333 [38]

Answer:

Step-by-step explanation:

The posssible factors are

x^2 + 4x - 32

(x+8)(x-4)

x^2+ 14x - 32

(x+16)(x-2)

(x+32)(x-1)

x^2+31x-32

8 0
4 years ago
PLS HELP ! Will give brainliest
Darina [25.2K]

Answer:

Step-by-step explanation:

The quadratic formula would be the following...

x = \frac{-b (+-)\sqrt{b^{2} - 4ac } }{2a}

where the original quadratic equation would be represented as follows

ax^{2} + bx +c = 0

Using this information and the information provided in the image we can plug in the quadratic equation values in the image to form the quadratic formula.

\frac{-(-20)±\sqrt{(-20)^{2} - 4(16)(-6) } }{2(16)}

That would be the correct order for the values.

3 0
3 years ago
After jumping rope for 15 minutes, Jan took a break. If Jan took a break at 3:05 p.M., at what time did she start jumping rope?
Kitty [74]

Answer: 2 : 50 pm

Step-by-step explanation:

If Jan took a break at 3:05 pm and she had been jumping rope for 15 minutes before that, to find the time she started jumping rope, subtract 15 from the current time:

= 3:05 - 15

= 2:50 pm

<em>Jan started jumping rope at 2 : 50 pm </em>

3 0
3 years ago
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