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Finger [1]
3 years ago
14

Hello!!:) Please help me answer 7-10 will give brainlst <3

Mathematics
1 answer:
KiRa [710]3 years ago
3 0

Answer:

7. Slope = -7/4

8. Slope = 2

9. Second Point = (0, 0)

10. Second Point = (0 ,-5)

Step-by-step explanation:

Find the slope: Slope Formula = y2-y1/x2-x1

7. (2, 4) and (6, -3)

x1,x2 = (2, 4) y1,y2 = (6, -3)

(-3 - 4)/(6 - 2)

-7/4

8. (-5, 1) and (-1, 9)

x1,x2 (-5, 1) y1,y2 (-1, 9)

(9 - 1)/(-1 - (-5))

8/4

2

Second Point on Line:

9. We know: slope = 1/2, and (2, 1) is on the line; So:

y = 1/2x + b where we have to still find b

so b = y1 - m * x1

b = 1 - 1/2 * 2

b = 1 - 1

b = (0,0)

If you plug this in to the slope formula, it comes out to 1/2

10. We know: slope = -4, and (-3, 7) is on the line; So

y = -4x + b where we have to still find b

so b = y1 - m * x1

b = 7 - (-4) * -3

b = 7 - 12

b = (0,-5)

If you plug this in to the slope formula, it comes out to -4

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4 years ago
Find the discriminant of x2-6x -10 = 0, and determine the number of real solutions of the equation.​
sergiy2304 [10]

Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

Standard Form: ax² + bx + c = 0

Discriminant: b² - 4ac

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  • Equal to 0 - 1 solution
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Step-by-step explanation:

<u>Step 1: Define</u>

x² - 6x - 10 = 0

<u>Step 2: Identify Variables</u>

<em>Compare quadratic.</em>

x² - 6x - 10 = 0 ↔ ax² + bx + c = 0

a = 1, b = -6, c = -10

<u>Step 3: Find Discriminant</u>

  1. Substitute in variables [Discriminant]:                                                            (-6)² - 4(1)(-10)
  2. [Discriminant] Evaluate exponents:                                                                36 - 4(1)(-10)
  3. [Discriminant] Multiply:                                                                                    36 + 40
  4. [Discriminant] Add:                                                                                          76

This tells us that our quadratic has 2 real solutions.

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Step-by-step explanation:

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