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2 years ago

Find the discriminant of x2-6x -10 = 0, and determine the number of real solutions of the equation.

Mathematics

1 answer:

sergiy2304 [10]2 years ago

8 0

Answer:

2 real solutions

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Standard Form: ax² + bx + c = 0

Discriminant: b² - 4ac

Positive - 2 solutions
Equal to 0 - 1 solution
Negative - No solutions/Imaginary

Step-by-step explanation:

Step 1: Define

x² - 6x - 10 = 0

Step 2: Identify Variables

Compare quadratic.

x² - 6x - 10 = 0 ↔ ax² + bx + c = 0

a = 1, b = -6, c = -10

Step 3: Find Discriminant

Substitute in variables [Discriminant]: (-6)² - 4(1)(-10)
[Discriminant] Evaluate exponents: 36 - 4(1)(-10)
[Discriminant] Multiply: 36 + 40
[Discriminant] Add: 76

This tells us that our quadratic has 2 real solutions.

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Step-by-step explanation:

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But we were given that,

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The correct answer is B

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Find the discriminant of x2-6x -10 = 0, and determine the number of real solutions of the equation.​

Find the discriminant of x2-6x -10 = 0, and determine the number of real solutions of the equation.