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Phantasy [73]
3 years ago
13

What integer best represents a gain of 5 gain

Mathematics
1 answer:
boyakko [2]3 years ago
8 0
A gain in yards would be positive, therefore the best representation of a gain of five yards would be 5.

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Charlie is standing 45 feet from the base of 100 foot tall tree. What is the angle of elevation from him to the kite stuck on to
galben [10]
Hey. Let me help you on this one.

In order for us to solve this problem easier, let's break it apart. We can also graph the triangle so we get visual of this problem.

I drew a quick graph for you to easier understand this question. As you can see, Charlie is standing below the tree 45 feet from it, and we need to find the unknown angle measure.

Let's form a SOHCAHTOA function which you have probably already learned in your Geometry course.

First of all let's identify our sides. The side opposite of the right triangle is a Hypotenuse, and the side that's 45 feet is adjacent, since it's adjacent to the unknown angle.

We know that we need to use Cos (Cosine) with negative power to it in order to solve this question, since we are looking for the unknown angle measure.

Let's form the function which Cos, Hypotenuse, and Adjacent side.

Cos^{-1} =45/100

Now, let's solve the left part of this function


Cos^{-1} =0.45

Awesome. You will need to use your calculator for this part. Find the value of 0.45 when negative Cosine is used on it.

Cos^{-1} =0.45
63.25631605

Awesome. Let's round this number to the closest tenth

63.3 is the rounded value we have discussed below.

Answer: 63.3 degrees is the unknown measure of the angle

5 0
2 years ago
Does the table represent a linear function? Why or why not.
Elza [17]

Answer:

B?

Step-by-step explanation:

4 0
2 years ago
If a/\2+1/a/\2=11, then a+1/a=?
Nadya [2.5K]

Answer:

\pm \sqrt{13}

Step-by-step explanation:

\bigg(a +  \frac{1}{a}  \bigg)^{2} =  {a}^{2}   +  \frac{1}{ {a}^{2} }  + 2 \times a \times  \frac{1}{a}  \\  \\ \bigg(a +  \frac{1}{a}  \bigg)^{2} = 11 + 2 \\  \\   \bigg(a +  \frac{1}{a}  \bigg)^{2} = 13 \\  \\  \bigg(a +  \frac{1}{a}  \bigg) =  \pm \sqrt{13}

5 0
3 years ago
Please solve this problem because tomorrow is my exam.<br><br>​
jonny [76]

Step-by-step explanation:

a). A = {x  ∈ R  I  5x-8 < 7}

5x - 8 < 7 <=> 5x < 8+7  <=> 5x < 15  =>

x < 3  => A = (-∞ ; 3)

A ∩ N = {0 ; 1 ; 2}

A - N* = (-∞ ; 3) - {1 ; 2}

b).  A = { x ∈ R  I  7x+2 ≤ 9}

7x+2 ≤ 9 <=> 7x ≤ 7  => x ≤ 1 => x ∈ (-∞ ; 1]

A ∩ N = {0 ; 1}

A-N* = (-∞ ; 1)

c). A = { x ∈ R  I  I 2x-1 I < 5}

I 2x-1 I < 5  <=> -5 ≤ 2x-1 ≤ 5  <=>

-4 ≤ 2x ≤ 6  <=> -2 ≤ x ≤ 3  => x ∈ [-2 ; 3]

A ∩ N = {0 ; 1 ; 2 ; 3}

A - N* = [-2 ; 3) - {1 ; 2}

d). A = {x ∈ R I I 6-3x I ≤ 9}

I 6-3x I ≤ 9  <=> -9 ≤ 6-3x ≤ 9  <=>

-15 ≤ -3x ≤ 3 <=> -5 ≤ -x ≤ 3  =>

-3 ≤ x ≤ 5  => x ∈ [-3 ; 5]

A ∩ N = {0 ; 1 ; 2 ; 3 ; 4 ; 5}

A - N* = [-3 ; 5) - {1 ; 2 ; 3 ; 4}

4 0
2 years ago
Please help and NO LINKS!
Zielflug [23.3K]

Answer:

2/100 is the answer to the question

8 0
2 years ago
Read 2 more answers
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