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Rasek [7]
2 years ago
15

Please help me no trolls 15 points

Mathematics
1 answer:
elixir [45]2 years ago
3 0
Option C is the correct graph.

She makes 96 pots every 12 days.
96/12 = 8, meaning she makes 8 pots every day.
You might be interested in
Solve this equation<br> 3x - 5 = -26​
Dmitry_Shevchenko [17]

3x - 5 = -26​

<u>step 1:</u>

subtract +5 on each side because you have to do the inverse operation

<u>step 2:</u>

3x= -21

<u>step 3:</u>

now divide 3 on each side

the answer is -7

<u />

Hope this helped!

<u />

<em>TheOneAndOnlyLara~</em>

5 0
1 year ago
Read 2 more answers
The area of the Indian Ocean is what percent of the area of the Pacific ocean? ROund to the nearest whole?show your work
Bumek [7]
Pacific
64/100
Indian
25/100
64/100-25/100=39/100
39/100=39%
I'm not sure but I think 39% is the answer. Better to google it ;)
4 0
3 years ago
A line has equation y=x−5. The line is shifted 3 units to the left and 1 unit up. Which points are on the graph of the line afte
Katyanochek1 [597]
This is one way to do it

5 0
3 years ago
In ABC, m∠A=10 and m∠B=145. Select the triangles that are similar to ABC.
Tanya [424]

Answer:

A

Step-by-step explanation:

A triangle has 180 degrees.

So, 10 + 145 + x = 180

x = 25

This means that the angles in the triangle are:

10, 145, and 25

Using this information, only A has the same values so it is the answer

3 0
3 years ago
The mayor of a town has proposed a plan for the construction of an adjoining bridge. A political study took a sample of 1700 vot
lara [203]

Answer:

z=\frac{0.66 -0.63}{\sqrt{\frac{0.63(1-0.63)}{1700}}}=2.562  

p_v =P(z>2.562)=0.0052  

So the p value obtained was a very low value and using the significance level given \alpha=0.02 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that at 2% of significance the proportion of voters that favored construction is higher than 0.63 or 63%.

Step-by-step explanation:

Data given and notation

n=1700 represent the random sample taken

\hat p=0.66 estimated proportion of voters that favored construction

p_o=0.63 is the value that we want to test

\alpha=0.02 represent the significance level

Confidence=98% or 0.98

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that percentage of residents who favor construction is more than 63%.:  

Null hypothesis:p \leq 0.63  

Alternative hypothesis:p > 0.63  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.66 -0.63}{\sqrt{\frac{0.63(1-0.63)}{1700}}}=2.562  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.02. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>2.562)=0.0052  

So the p value obtained was a very low value and using the significance level given \alpha=0.02 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that at 2% of significance the proportion of voters that favored construction is higher than 0.63 or 63%.

7 0
3 years ago
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