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Rasek [7]
3 years ago
15

Please help me no trolls 15 points

Mathematics
1 answer:
elixir [45]3 years ago
3 0
Option C is the correct graph.

She makes 96 pots every 12 days.
96/12 = 8, meaning she makes 8 pots every day.
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Solve the equation. Write your answer as an integer or simplified fraction.
saw5 [17]

<u>Corrected question :</u>

Solve the equation. Write your answer as an integer or simplified fraction.

  • 8n - 7 (n - 2) = 18

<u>Required Solution :</u>

The given equation,

  • 8n - 7 (n - 2) = 18

★ Multiplying -7 into (n - 2),

>> 8n - 7 × (n - 2) = 18

>> 8n - 7n + 14 = 18

★ On substracting 7n from 8n we gets,

>> n + 14 = 18

★ Now transposing 14 which is in L.H.S. into R.H.S. (Remember that sign would be . So 14 would be -14),

>> n = 18 - 14

>> n = 14

★ Therefore,

  • Value of n is 14.

<u>Learn</u><u> more</u><u> from</u><u> brainly</u><u>.</u><u>c</u><u>o</u><u>m</u><u> </u><u>:</u>

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6 0
2 years ago
What does this means
Dennis_Churaev [7]
Is the number that satys the same the number that changes the number that conrtolles them
4 0
3 years ago
Whats 56753 ÷ 43 = ????????????????????????????????????????????
dalvyx [7]

Answer:

1,319.83721

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Which expression can be used to find the area of the square? Question 4 options: 2(6.4+6.4) 6.4² 6.4×2 2(6.4×6.4)
Nimfa-mama [501]
Option 2 => 6.4^2
Because area of a square = side *side or side^2
Hope this helps u..!!!
6 0
3 years ago
The distance around a meter is 9619 ft. find the diameter of the crater .use 22/7 for pie
DochEvi [55]
The circumference of a circle is found with the equation

C = 2 pi * r

Since we have the circumference we can find the radius.  Then once we have the radius we can determine the diameter.

9619 = 2 (22/7) r
multiply each side by 7

67333 = 2*22*r
67333 = 44r

divide each side by 44
r = 67333/44 = 1530.295 rounded to the nearest hundredth = 1530.30

The diameter is 2 x the radius, so

1530.30 x 2 = 3060.6 ft

The diameter of the crater is 3060.6 ft
7 0
3 years ago
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