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Artyom0805 [142]
3 years ago
8

There's 754 students going to a field trip. There are only 23 buses. If only 4 students can ride each bus, how many buses will y

ou need to bring ALL the students ?
Mathematics
1 answer:
ddd [48]3 years ago
6 0
186 buses. The answer is 188.5, but you cannot ride in 188 and a half buses.
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Determine if the triangles are congruent. If yes, by which theorem?
klio [65]

Answer:

Yes ASA.

Step-by-step explanation:

ASA

6 0
3 years ago
Which situation is represented by the equation 6n+5=3n+20
balandron [24]

Answer:

a linear equation

Step-by-step explanation:

6n+5=3n+20

<u>collect like terms</u><u>:</u>

6n-3n=20-5

3n=15

<em><u>divide both sides with the coefficient of n</u></em>

3n÷3=15÷3

n=5

7 0
3 years ago
Which answer is the approximate standard deviation of the data set?
Ierofanga [76]

Answer:  A. 6.5

Step-by-step explanation:

Here, the given set = { 15, 19 3, 12, 17, 2, 2, 8}

Mean, \overline{ x} = \frac{15+19+3+12+17+2+2+8}{8} = \frac{78}{8} = 9.75

Number of elements, n = 8

\frac{\sum (|x-\overline{x}|)^2}{n}=42.4375

Thus, the standard deviation, \sigma =\frac{\sqrt{\sum(|x-\overline{x}|)^2} }{n}=\sqrt{\frac{339.5}{8}}=\sqrt{42.4375} = 6.51440711\approx 6.5

⇒ Option A is correct.

4 0
3 years ago
Read 2 more answers
The length of each side of a square is 3 inches more than the length of each side of a smaller square the sum of the areas of th
Svetradugi [14.3K]
The length of each side of a square is 3 in. more than the length of each side of a smaller square. The sum of the areas of the squares is 149 in. $^{2} .$ Find the lengths of the sides of the two squares.
4 0
3 years ago
Use the scale drawing and the scale factor to enlarge a square that has a side length of 12 in. Scale factor= 3 in:2m.
podryga [215]

Given:

The side of square = 12 in.

Scale factor of enlargement = 3 in : 2 m

To find:

The proportion that is use to solve the side length, x, of the enlarged square.

Solution:

Let, the side of length of enlarged square = x m

In case of enlargement the corresponding sides are proportional.

\dfrac{3}{12}=\dfrac{2}{x}

3x=2\times 12

3x=24

Divide both sides by 3.

x=\dfrac{24}{3}

x=8

Therefore, the required proportion is \dfrac{3}{12}=\dfrac{2}{x} and the side length of the square after enlargement is 8 m.

4 0
3 years ago
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