we are given that
angle(ACF)=90
angle(ACB)=61
sum of all angles along any line is 180
so, we get
angle(ACF)+angle(ACD)=180
we can plug value
90+angle(ACD)=180
angle(ACD)=90
now, we can use formula
angle(ACD)=angle(ACB)+angle(BCD)
now, we can plug values
and we get
90=61+angle(BCD)
90-61=61-61+angle(BCD)
angle(BCD)=29................Answer
The nearest ten thousand is 20,000
It's the first choice.Correlation that implies causation
Event 4 (impossible), Event 3 (probability is 7/20), Event 1 (probability is 6/12 which is greater than 7/20), and Event 2 (certain to happen)