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forsale [732]
3 years ago
5

Can anyone answer this for me?

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
5 0
The answer to problem #2 is,

( x , y ) ==> ( - x , - y )

All of them were rotated 180° clockwise which is the same as 180° counterclockwise.

~~

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey
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Amy is correct because a nonlinear association could increase along the whole data set, while being steeper in some parts than others. The scatterplot could be linear or nonlinear.

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Write (p^4)^2 without exponents
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Triangle RST has vertices located at R (2, 3), S (4, 4), and T (5, 0).
LiRa [457]

The length of the sides are 2.24, 4.24 and 4.12 units while the slope are 0.5, -1 and -4.

<h3>Linear equation</h3>

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the initial value of y.

For RS:

  • Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(4-3)^2+(4-2)^2}=2.24   \\&#10;\\&#10;slope=\frac{y_2-y_1}{x_2-x_1} =\frac{4-3}{4-2}=0.5

For RT:

  • Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(0-3)^2+(5-2)^2}=4.24   \\&#10;\\&#10;slope=\frac{y_2-y_1}{x_2-x_1} =\frac{0-3}{5-2}=-1

For ST:

  • Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(0-4)^2+(5-4)^2}=4.12   \\&#10;\\&#10;slope=\frac{y_2-y_1}{x_2-x_1} =\frac{0-4}{5-4}=-4

The length of the sides are 2.24, 4.24 and 4.12 units while the slope are 0.5, -1 and -4.

Find out more on linear equation at: brainly.com/question/14323743

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