The length in units of the line segment A'B' in the resulting figure is the same as the length of line segment AB in the previous rectangle.
<h3>Translation of shapes in the Cartesian plane</h3>
Form the task content;
- It follows that the initial rectangle A is only translated and hence, the size of each of its sides remains constant.
The translation which occurs on the rectangle only shifts the whole rectangle leftward and downward and hence, each line segment in the rectangle still retains its length.
Read more on translation in the Cartesian plane;
brainly.com/question/5471952
The correct answer is 1/8.
Use the chain rule:
<em>y</em> = tan(<em>x</em> ² - 5<em>x</em> + 6)
<em>y'</em> = sec²(<em>x</em> ² - 5<em>x</em> + 6) × (<em>x</em> ² - 5<em>x</em> + 6)'
<em>y'</em> = (2<em>x</em> - 5) sec²(<em>x</em> ² - 5<em>x</em> + 6)
Perhaps more explicitly: let <em>u(x)</em> = <em>x</em> ² - 5<em>x</em> + 6, so that
<em>y(x)</em> = tan(<em>x</em> ² - 5<em>x</em> + 6) → <em>y(u(x))</em> = tan(<em>u(x)</em> )
By the chain rule,
<em>y'(x)</em> = <em>y'(u(x))</em> × <em>u'(x)</em>
and we have
<em>y(u)</em> = tan(<em>u</em>) → <em>y'(u)</em> = sec²(<em>u</em>)
<em>u(x)</em> = <em>x</em> ² - 5<em>x</em> + 6 → <em>u'(x)</em> = 2<em>x</em> - 5
Then
<em>y'(x)</em> = (2<em>x</em> - 5) sec²(<em>u</em>)
or
<em>y'(x)</em> = (2<em>x</em> - 5) sec²(<em>x</em> ² - 5<em>x</em> + 6)
as we found earlier.
Answer:
An 8 inch Circle has a diameter of 8 inch, whereas the 8 inch square has length and width of 8 inch
Step-by-step explanation:
For a circle to be an 8 inch, the diameter should be 8 inches. Square's sides are equal, so we would have 8 inches on each side of the square. The area of this 8 inch square would be 64 in^2, whereas the 8 inch circle's area is 50.24 inch ^2. (because (3.14)(r^2))
