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Montano1993 [528]
3 years ago
13

The dimensions of a rectangle are 2 x − 5 and 3 x + 3 . Which expression represents the area of the rectangle in simplest terms?

A. 6 x 2 − 9 x − 15 B. 6 x 2 − 9 x + 15 C. 6 x 2 + 9 x − 15 D. 6 x 2 − 15 x − 9
Mathematics
1 answer:
andrew11 [14]3 years ago
8 0

Answer:

A

Step-by-step explanation:

The area of a rectangle is the product of its dimensions, that is

A = (2x - 5)(3x + 3) ← expand using FOIL

  = 6x² + 6x - 15x - 15 ← collect like terms

  = 6x² - 9x - 15 → A

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A boat heading out to sea starts out at Point A, at a horizontal distance of 804 feet from a lighthouse/the shore. From that poi
marishachu [46]

Answer: 672 feets

Step-by-step explanation:

Using the solution diagram attached, the vertical height, h of the lighthouse ;

Using trigonometry :

Tanθ = opposite / Adjacent

Tan 2 = h / 804

h = tan 2 * 804

h = 28.076 feets

Using h, we can obtain the distance CB :

Tan θ = opposite / Adjacent

Tan 2 = 28.076 / CB

CB = 28.076 / Tan 12°

CB = 132.08860 feets

Distance between A and B

804 - 132.08860

= 671.9 feets

6 0
3 years ago
HELPP!!
Brilliant_brown [7]

Answer:

Hope this will help you.

5 0
3 years ago
Determine the end behavior of each rational function below. <br> f(x) = 7x3 + 2 / 4x5 − 3x + 1
Tems11 [23]

Answer:

When x ⇒ +∞ and x ⇒ -∞, f(x) ⇒ 0 from the positive region.

Step-by-step explanation:

Hi there!

Let´s write the function:

f(x) = (7x³ + 2) / (4x⁵ - 3x + 1)

When x ⇒ +∞ we can neglect the constant values (2 and 1). So:

f(x) ⇒ 7x³ /(4x⁵ - 3x)

f(x) ⇒ 7x³ / x(4x⁴ - 3)

f(x) ⇒ 7x² / 4x⁴

f(x) ⇒ 7/4x² ⇒ 0 from the positive region

when x ⇒ -∞

f(x) ⇒ 7/ 4x² ⇒ 0 from the positive region because x² is always positive.

Then when x is a very big number (positive or negative), f(x) will be approximately 0 and positive.

4 0
3 years ago
Help! Look at attachment
Margaret [11]

Answer: A

Step-by-step explanation: A keeps the same slope of 1/4 from what can be seen and B is constantly changin, so for me it is A. Hope it helps.

3 0
3 years ago
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Helppppp! Angles PTQ and STR are vertical angles and congruent. Circle T is shown. Line segments T P, T Q, T R, and T S are radi
cestrela7 [59]

Answer:

\overline{QP} = \overline{SR}

Step-by-step explanation:

Given: ∠PTQ ≅ ∠STR and TP, TQ, TR and TS are radii of the circle.

If  two angle are equal, then they are equal in size and their measurements are equal.

IF ∠PTQ ≅ ∠STR then they are also equal in their measurements.

Now, In ΔPTQ and ΔSTR

∠PTQ ≅ ∠STR  (vertically opposite angle)

\overline{TQ} \cong \overline{ST}  (Radius of the circle are equal and congruent in length)

\overline{PT} \cong \overline{TR}  (Radius of the circle)

∴ ΔPTQ ≅ ΔSTR (SAS postulate)

∴ \overline{QP}\cong \overline{SR} (corresponding sides of congruent triangle are equal  and congruent).

6 0
3 years ago
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