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3 years ago

3 (5x + 7) = 75 what is x?

Mathematics

1 answer:

iren [92.7K]3 years ago

7 0

5x divided by 5
18 divided by 5
X= 18/5 or 3.6

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What is the next 3 term sequence for 1,3,7,13,21 how do you solve it

skad [1K]

Answer:

1,3,7,13,21,31,43,57

Step-by-step explanation:

It s increasing by two each time.

1+2=3

3+4=7

7+6=13

etc.

8 0

3 years ago

I am confused about 11.

babunello [35]

-90.1 is the answer.

7 0

4 years ago

Challenge You have 2 different savings accounts. For Account A, the simple interest earned after 3 months is $1.60. For Account

const2013 [10]

Answer:

$1.28

Note for you:

I hope this helps!

Answer and Step-by-step explanation:

The computation is shown below;

As we know that

The simple interest is

Simple interest = Principal × rate × time

For Account A, the principal would be

2 = Principal × 3.2% × 3

So, the principal is $20.83

For account B, the principal would be

38.50 = Principal × 2.2% × 30

So, the principal is $58.33

Now the interest for both the accounts are as follows

For account 1

= $20.83 × 3.2%

= $0.67

And, for the account 2

= $58.33 × 2.2%

= $1.28

As it can be seen that the account 2 has the highest interest

The same is to be considered

4 0

2 years ago

Last year, Keiko had $20,000 to invest. She invested some of it in an account that paid %7 simple interest per year, and she inv

erma4kov [3.2K]

Answer:

$P_2 = \$6,000\\P_1 = \$14,000$

Step-by-step explanation:

The formula of simple interest is:

$I = P_0rt$

Where I is the interest earned after t years

r is the interest rate

$P_0$ is the initial amount

We know that the investment was $20,000 in two accounts

_______________________________________________

For the first account r = 0.07 per year.

Then the formula is:

$I_1 = P_1r_1t$

Where

$P_1$ is the initial amount in account 1 at a rate $r_1$ during t = 1 year

$I_1 = P_1(0.07)(1)\\\\I_1 = 0.07P_1$

For the second account r = 0.05 per year.

Then the formula is:

$I_2 = P_2r_2t$

Where

$P_2$ is the initial amount in account 2 at a rate $r_2$ during t = 1 year

Then

$I_2 = P_2(0.05)(1)\\\\I_2 = 0.05P_2$

We know that the final profit was I $1,280.

$I = I_1 + I_2=1,280$

Substituting the values $I_1$ , $I_2$ and I we have:

$1,280 = 0.07P_1 + 0.05P_2$

As the total amount that was invested was $20,000 then

$P_0 = P_1 + P_2 = 20,000$

Then we multiply the second equation by -0.07 and add it to the first equation:

$0.07P_1 + 0.05P_2 = 1.280\\.\ \ \ \ \ \ \ \ +\\-0.07P_1 -0.07P_2 = -1400\\-------------$

$-0.02P_2 = -120\\\\P_2 = 6,000$

Then $P_1 = 14,000$

4 0

3 years ago

Use the quadratic formula to solve x-6x+8=0

Sedbober [7]

x = [-(-6) +/- sqrt((-6)^2 - 4*1 * 8))] / 2

= (6 + sqrt4) / 2 , ( 6 - sqrt4)/2

= 4 , 2

6 0

4 years ago