Answer:
<em>2 solutions</em>
Step-by-step explanation:
Given the expression
2m/2m+3 - 2m/2m-3 = 1
Find the LCM of the expression at the left hand side:
2m(2m-3)-2m(2m+3)/(2m+3)(2m-3) = 1
open the bracket
4m²-6m-4m²-6m/(4m²-9) = 1
Cross multiply
4m²-6m-4m²-6m = 4m² - 9
-12m = 4m² - 9
4m² - 9+12m = 0
4m² +12m-9 = 0
<em>Since the resulting equation is a quadratic equation, it will have 2 solutions since the degree of the equation is 2</em>
Honestly I don't know that is a really hard question
This is because logarithm has its own set of properties that is different from algebra. The term log(3x - 1) is equivalent to log 3x/log 1. If we continue to rearrange and find x, the solution would be:
log(3x - 1) = log28
log 3x/log 1 = log 28
log 3x = log 28 * log 1 = 0
3x = 10⁰ = 1
3x = 1
x = 1/3
<em>So, that means 3x - 1 = 3(1/3) - 1 = 0.</em>
Let n be the amount of 80% solution; and 150-n be the amount of 20% solution. Then:
.8n+.2(150-n)=.6(150)
.8n+30-.2n=90
.6n=60
n=100
150-n=50
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