Answer:
6.25 % of area of Large triangle = area of smallest triangle
Step-by-step explanation:
Area of large triangle L = (1/2)*base*height
L = (1/2)*(44 m)* h
L = 22*h square m.
2nd equilateral triangle area: S =(1/2)*(22 m)*(0.5h)
S = 5.5*h sq. m.
3rd smallest equilateral triangle area : T = (1/2)*(11 m)*(0.25h)
T = 1.375*h sq. m
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Find percent P where T = P* L, 1.375*h = P * 22*h
P = 6.25% = 0.0625
Simplifying
3x + 4 = 7 + -2x
Reorder the terms:
4 + 3x = 7 + -2x
Solving
4 + 3x = 7 + -2x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '2x' to each side of the equation.
4 + 3x + 2x = 7 + -2x + 2x
Combine like terms: 3x + 2x = 5x
4 + 5x = 7 + -2x + 2x
Combine like terms: -2x + 2x = 0
4 + 5x = 7 + 0
4 + 5x = 7
Add '-4' to each side of the equation.
4 + -4 + 5x = 7 + -4
Combine like terms: 4 + -4 = 0
0 + 5x = 7 + -4
5x = 7 + -4
Combine like terms: 7 + -4 = 3
5x = 3
Divide each side by '5'.
x = 0.6
Answer: x = 0.6
Using a calculator: cos 70 deg = 0.342. Note: it sounds as tho' you were given several answer options. Where are they?
Answer: (13 + y) / 5
Step-by-step explanation:
Since Grandma Gertrude gave 13 pieces of jewelry and Grandma Fien gave y pieces of jewelry to the Carlson sisters, the total jewellery given to the sisters will be:
= 13 + y
Since there are 5 Carlson sisters, the number of pieces of jewelry that each sister receive will be:
= Total jewelries / Number of sisters
= (13 + y) / 5
Answer:The claim is correct
Explanation:Assume the given triangle ABCperimeter of triangle ABC = AB + BC + CA ............> I
Now, we have:D is the midpoint of AB, this means that:
AD = DB = (1/2) AB ..........> 1E is the midpoint of AC, this means that:
AE = EC = (1/2) AC ...........> 2DE is the midsegment in triangle ABC, this means that:
DE = (1/2) BC ...........> 3perimeter of triangle ADE = AD + DE + EA
Substitute in this equation with the corresponding lengths in 1,2 and 3:perimeter of triangle ADE = (1/2) AB + (1/2) BC = (1/2) AC
perimeter of triangle ADE = (1/2)(AB+BC+AC) .........> IIFrom I and II, we can prove that:perimeter of triangle ADE = (1/2) perimeter of triangle ABC
Which means that:perimeter of midsegment triangle is half the perimeter of the original triangle.
Hope this helps :)