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Lerok [7]
3 years ago
5

Help me please I don’t know the answer

Mathematics
1 answer:
N76 [4]3 years ago
6 0
(1.9x1)+(1.9x5.6)=12.54
The answer is 12.54 cm^2 (the second option)
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the shadow of a statue is 20 feet long while the shadow of a student is 4ft long. if the student is 6ft tall how tall is the sta
zaharov [31]

Answer:

<h2>30 ft. tall</h2><h2 />

Step-by-step explanation:

ratio and proportion:

<u>20 ft. long</u>  =  <u> 4 ft. long</u>

  x tall             6 ft. tall

4 (x) = 20 (6)

x = 120 / 4

x = 30 ft. tall

3 0
3 years ago
Help picture below problem 16
Allisa [31]

Answer:

5

Step-by-step explanation:

a²+b²=c²

In this case c is 13 and b is 12

a²+12²=13³

a²+144=169

Subtract 169 and 144 to find a

169-144=25

The square root of 25 is 5

5 0
3 years ago
Use matrices to determine the coordinates of the vertices of the reflected figure. Then graph the pre-image and the image on the
Troyanec [42]

Answer:

The coordinates of the vertices of the reflected figure are :

R' is (5 , -2) , S' is (3 , 5) , T' is (-7 , 6) ⇒ the right answer is (d)

Step-by-step explanation:

* When you reflect a point across the line y = x, the x-coordinate

 and y-coordinate change their places.

- If the point is (x , y) then its image is (y , x)

* If you reflect over the line y = -x, the x-coordinate and y-coordinate

 change their places and their signs

- If the point is (x , y) then its image is (-y , -x)

* Lets study the matrix of the reflection  about the line y = x

- The matrix of the reflection about the line y = x is

 \left[\begin{array}{cc}0&1\\1&0\end{array}\right]

- Because the x-coordinate and y-coordinate change places.

* Now lets solve the problem

- We will multiply the matrix of the reflection about y = x

 by each point to find the image of each point

- The dimension of the matrix of the reflection about y = x

 is 2×2 and the dimension of the matrix of each point is 2×1,

 then the dimension of the matrix of each image is 2×1

∵ The point R is (-2 , 5)

∴ R'=\left[\begin{array}{cc}0&1\\1&0\end{array}\right]\left[\begin{array}{cc}-2\\5\end{array}\right]=

  \left[\begin{array}{c}(0)(-2)+(1)(5)\\(1)(-2)+(0)(5)\end{array}\right]=\left[\begin{array}{c}5\\-2\end{array}\right]

∴ R' is (5 , -2)

∵ The point S is (5 , 3)

∴ S'=\left[\begin{array}{cc}0&1\\1&0\end{array}\right]\left[\begin{array}{c}5\\3\end{array}\right]=

  \left[\begin{array}{c}(0)(5)+(1)(3)\\(1)(5)+(0)(3)\end{array}\right]=\left[\begin{array}{c}3\\5\end{array}\right]

∴ S' is (3 , 5)

∵ The point T is (6 , -7)

∴ T'=\left[\begin{array}{cc}0&1\\1&0\end{array}\right]\left[\begin{array}{c}6\\-7\end{array}\right]=

  \left[\begin{array}{c}(0)(6)+(1)(-7)\\(1)(6)+(0)(-7)\end{array}\right]=\left[\begin{array}{c}-7\\6\end{array}\right]

∴ T' is (-7 , 6)

* Lets look to the figures to find the right answer

∵ The R' is (5 , -2) , S' is (3 , 5) , T' is (-7 , 6)

∴ The right answer is (d)

4 0
4 years ago
IM RUNNING OUT IF TIME CAN SOMEONE PLEASE HELP
Elenna [48]

Answer:

the third option

Step-by-step explanation:

hope this helps! have a good day and stay safe!

3 0
3 years ago
Which of the following described (5+5) in the expression above?
Y_Kistochka [10]

Answer:

10

Step-by-step explanation:

its 5+5

8 0
4 years ago
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