The table of values of the function y = 2x^2 is:
x 0 1 2 3 4
y 0 2 8 18 32
<h3>How to complete the table?</h3>
The equation of the function is given as:
y = 2x^2
When x= 0, we have
y = 2 * 0^2 = 0
When x= 1, we have
y = 2 * 1^2 = 2
When x= 2, we have
y = 2 * 2^2 = 8
When x= 3, we have
y = 2 * 3^2 = 18
When x= 4, we have
y = 2 * 4^2 = 32
So, the table of values is:
x 0 1 2 3 4
y 0 2 8 18 32
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<span>Simplifying
0x + 7 + 5x = 2x + 30 + 40
Anything times zero is zero.
0x + 7 + 5x = 2x + 30 + 40
Combine like terms: 0 + 7 = 7
7 + 5x = 2x + 30 + 40
Reorder the terms:
7 + 5x = 30 + 40 + 2x
Combine like terms: 30 + 40 = 70
7 + 5x = 70 + 2x
Solving
7 + 5x = 70 + 2x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-2x' to each side of the equation.
7 + 5x + -2x = 70 + 2x + -2x
Combine like terms: 5x + -2x = 3x
7 + 3x = 70 + 2x + -2x
Combine like terms: 2x + -2x = 0
7 + 3x = 70 + 0
7 + 3x = 70
Add '-7' to each side of the equation.
7 + -7 + 3x = 70 + -7
Combine like terms: 7 + -7 = 0
0 + 3x = 70 + -7
3x = 70 + -7
Combine like terms: 70 + -7 = 63
3x = 63
Divide each side by '3'.
x = 21
Simplifying
x = 21</span>
C. Savings account B because it has more compounding periods per year.
Step-by-step explanation:
Step 1:
Savings account A has an APR of 5% which compounds interest semiannually. This means that savings account A compounds twice in a year. If account A compounds 5% a time, it would compound 5(2) = 10% in a single year.
Step 2:
Savings account B also has an APR of 5% which compounds interest quarterly. This means that savings account B compounds four times in a year. If account B compounds 5% a time, it would compound 5(4) = 20% in a single year.
Step 3:
Savings account A gets an interest of 5% a year while savings account B gets an interest of 10% so account B offers a higher APR because of more compoundings in a year.
Answer:
B
Step-by-step explanation:
