The 5th term in a geometric sequence is 120. The 7th term is 30. What are the possible values of the 6th term of the sequence.
1 answer:
Answer:
± 60
Step-by-step explanation:
aₙ = a₁ * rⁿ⁻¹
a₇ = 30 = a₁ * r⁷⁻¹ = a₁ * r⁶ (1)
a₅ = 120 = a₁ * r⁵⁻¹ = a₁ * r⁴ (2)
(1)/(2): 30/120 = 1/4 = r²
r = ± 1/2 or ± 0.5
a₁ = a₇/r⁶ = 30/0.5⁶ = 1920
a₆ = 1920 * (± 1/2)⁶⁻¹ = 1920 * ± 1/32 = ± 60
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5(n+6)=48
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Answer:
Step-by-step explanation:
a) 3x^2-12x-11=3*x^2-3*2*2*x+3*4-23=3*(x^2-2*2x+2^2)-23=3*(x-2)^2-23
so a= -2 ,b= -23
b) x1=[12+V(12^2-4*3* -11)]/6=12/6+V(144+132)/6=2+2/6V69=2+1/3V69=
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c=2, d= 23/3
