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noname [10]
3 years ago
14

What’s the largest common prime number in 8x2y, 24y2, 18xy

Mathematics
1 answer:
Feliz [49]3 years ago
6 0

Answer:

24y2

Step-by-step explanation:

i did a test similar to this question and got the answer correct

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Help plzzzzzzzzzzzzz​
zubka84 [21]

Answer:

RU=140

Step-by-step explanation:

Since ST=40 and VW=90 it goes up by 50 each time so....

RU

_______

90

+50

______=

140

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3 0
3 years ago
Read 2 more answers
Express tan A as a ratio with a rationalized denominator.
Hitman42 [59]
tan A = opposite/ adjacent , so it is equal to 7/ 4V2, or 7V2/4 which is answer B
5 0
2 years ago
The length of the base of a triangle is twice its height. if the area of the triangle is 44 square​ kilometers, find the height
xeze [42]
Let
x
be the height of the triangle.

Formular for area of Triangle
= ½ × base × height






thus,
{ \frac{1}{2} }(2x)(x)=44\ kilometers^2

Simplifying
x^2=44\ kilometers^2 \\\\ x= \sqrt{ 44 } \\\\ x=6.63\ kilometers
3 0
3 years ago
A rocket carrying fireworks is launched from a hill 60 feet above a lake. The rocket will fall into the lake after exploding at
castortr0y [4]

Answer:

<h3>A) 204m</h3><h3>B) 188m</h3>

Step-by-step explanation:

Given the rocket's height above the surface of the lake given by the function h(t) = -16t^2 + 96t + 60

The velocity of the rocket at its maximum height is zero

v = dh/dt = -32t + 96t

At the maximum height, v  = 0

0 = -32t + 96t

32t = 96

t = 96/32

t = 3secs

Substitute t = 3 into the modeled function to get the maximum height

h(3) = -16(3)^2 + 96(3) + 60

h(3) = -16(9)+ 288 + 60

h(3) = -144+ 288 + 60

h(3) = 144 + 60

h(3) = 204

Hence the maximum height reached by the rocket is 204m

Get the height after 2 secs

h(t) = -16t^2 + 96t + 60

when t = 2

h(2) = -16(2)^2 + 96(2) + 60

h(2) = -64+ 192+ 60

h(2) = -4 + 192

h(2) = 188m

Hence the height of the rocket after 2 secs is 188m

3 0
3 years ago
Simplify the following:
Charra [1.4K]
1) 4x + 5
2) 14w2 - 4w
3) -x + 19
4) 19x - 16
5) -x2 - x
6) 11a2b - 12ab2
5 0
2 years ago
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