A computer has a cache and main memory. 20 ns are required to reference a word that is in the cache. If the word is in main memo
1 answer:
Answer:
Explanation:
Given Information:
There are 3 possible cases
1. Location of reference word is in cache
2. Location of reference word is not in cache but in main memory
3. Location of reference word is neither in cache nor in main memory
The average time required to access a referenced word on this system is simply the sum of above 3 cases
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Answer:
Explanation:
The following Java code uses JavaFX to create a canvas in order to fit the 10x10 matrix and then automatically and randomly populates it with 0's and 1's using the setText method to set the values as a String
import javafx.application.Application;
import javafx.scene.Scene;
import javafx.scene.control.TextField;
import javafx.scene.layout.GridPane;
import javafx.stage.Stage;
public class Main extends Application {
private static final int canvasHEIGHT = 300;
private static final int canvasWIDTH = 300;
public void start(Stage primaryStage) {
GridPane pane = new GridPane();
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
TextField text = new TextField();
text.setText(Integer.toString((int)(Math.random() * 2)));
text.setMinWidth(canvasWIDTH / 10.0);
text.setMaxWidth(canvasWIDTH / 10.0);
text.setMinHeight(canvasHEIGHT / 10.0);
text.setMaxHeight(canvasHEIGHT / 10.0);
pane.add(text, j, i);
}
}
Scene scene = new Scene(pane, canvasWIDTH, canvasHEIGHT);
primaryStage.setScene(scene);
primaryStage.setMinWidth(canvasWIDTH);
primaryStage.setMinHeight(canvasHEIGHT);
primaryStage.setTitle("10 by 10 matrix");
primaryStage.show();
}
public static void main(String[] args) {
Application.launch(args);
}
}
