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Leona [35]
4 years ago
13

Assume that​ women's heights are normally distributed with a mean given by mu equals 61.4 in​, and a standard deviation given by

sigma equals 3.7 in.A) If a woman is randomly selected, find the probability that her height is less than 65 inches.B) If 34 women are randomly selected, find the probability that they have a mean height less than 65 inches.I think I know how to do this one but I want to be certain so please show your work so I can learn from you.
Mathematics
1 answer:
GuDViN [60]4 years ago
3 0
I think that the correct answer is A
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son4ous [18]
12) LCM of 2 & 12 is 12 
Answer: (F)

13) (25 x 8) x 4
Step 1: Order of operations do parenthesis first: (25 x 8) = 200
Step 2: Multiply: 200 x 4 = 800
Answer: 800

14) I would plug each value in to see which works
D) 10x + 5y = 10(6) + 5(9) = 60 + 45 = 105

Answer is (D)

15) 2 x 12 - 8 (divided by) 2^2
Exponent first: 2 x 12 - 8 divided by 4
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4 years ago
Solve the simultaneous equation 3x²-xy=0, 2y-5x=1​
White raven [17]

Answer:

exact Form:(0,),(1,3)

Equation Form: ( 0, )

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Step-by-step explanation:

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3 years ago
Find the roots of h(t) = (139kt)^2 − 69t + 80
Sonbull [250]

Answer:

The positive value of k will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80, roots are those values of t so that h(t) = 0. That is:

19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0 (1)

Roots are determined analytically by the Quadratic Formula:

t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}

t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }

The smaller root is t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }, and the larger root is t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }.

h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80 has one real root when \frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0. Then, we solve the discriminant for k:

\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}

k \approx \pm 0.028

The positive value of k will result in exactly one real root is approximately 0.028.

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