Answer: At least 713 paintballs
Step-by-step explanation:
Based on the information that has been given in the question, the inequality that'll be used to solve the question will be:
18+0.08B≥75
0.08B≥75-18
0.08B≥57
B≥57/0.08
B≥712.5
Carolina needs to buy at least 713 paintballs along with the entrance fee to get the promotion.
Answer:
The answer to your question is below
Step-by-step explanation:
Question 1.
We have the opposite side and the adjacent side so use the tangent to find x.
tan Ф = 
Substitution
tan Ф = 
Ф = 30.96° = x
Question 2.
Letter A is the correct answer
Letter B is incorrect because the cylinder does not have a height of 15 mm
Letter C is incorrect because of the radius of the sphere is not 6 mm
Letter D is incorrect because the radius of the sphere is not 6 mm and the height of the cylinder is not 15 mm.
Question 3.
To solve this exercise we use the trigonometric function tangent
tan Ф = 
Solve for opposite site
Opposite side = Adjacent side tanФ
Opposite side = 30 tan 80
d = 170.14 ft
Question 4
To find the sine, first we must calculate the opposite side
c² = a² + b²
a² = c² - b²
a² = 4² - 3²
a² = 16 - 9
a² = 7
a = 
sin A = 
sin A = 0.6614
Given the following data table that describes results from groups of 10
births from 10 different sets of parents. The random variable x
represents the number of girls among 10 children.
![\begin{tabular} {|c|c|} x&p(x)\\[1ex] 0&0.005\\ 1&0.014\\ 2&0.037\\ 3&0.114\\ 4&0.208\\ 5&0.241\\ 6&0.202\\ 7&0.116\\ 8&0.037\\ 9&0.013\\ 10&0.013\\[1ex] &\Sigma p(x)=1 \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7C%7D%0Ax%26p%28x%29%5C%5C%5B1ex%5D%0A0%260.005%5C%5C%0A1%260.014%5C%5C%0A2%260.037%5C%5C%0A3%260.114%5C%5C%0A4%260.208%5C%5C%0A5%260.241%5C%5C%0A6%260.202%5C%5C%0A7%260.116%5C%5C%0A8%260.037%5C%5C%0A9%260.013%5C%5C%0A10%260.013%5C%5C%5B1ex%5D%0A%26%5CSigma%20p%28x%29%3D1%0A%5Cend%7Btabular%7D)
The range rule of thumb says that the range is about four times the standard deviation.
We obtain the standard deviation as follows:
![\begin{tabular} {|c|c|p{2.3cm}|c|c|} x&p(x)&xp(x)&\left(x-E(x)\right)&\left(x-E(x)\right)^2\\[1ex] 0&0.005&0&-5.034&25.341\\ 1&0.014&0.014&-4.034&16.273\\ 2&0.037&0.074&-3.034&9.205\\ 3&0.114&0.342&-2.034&4.137\\ 4&0.208&0.832&-1.034&1.069\\ 5&0.241&1.205&-0.034&0.001\\ 6&0.202&1.212&0.966&0.933\\ 7&0.116&0.812&1.966&3.865\\ 8&0.037&0.296&2.966&8.797\\ 9&0.013&0.117&3.966&15.729\\ 10&0.013&0.13&4.966&24.661\\[1ex] &\Sigma p(x)=1&E(x)=\Sigma xp(x)=5.034 \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%20%7B%7Cc%7Cc%7Cp%7B2.3cm%7D%7Cc%7Cc%7C%7D%20x%26p%28x%29%26xp%28x%29%26%5Cleft%28x-E%28x%29%5Cright%29%26%5Cleft%28x-E%28x%29%5Cright%29%5E2%5C%5C%5B1ex%5D%200%260.005%260%26-5.034%2625.341%5C%5C%201%260.014%260.014%26-4.034%2616.273%5C%5C%202%260.037%260.074%26-3.034%269.205%5C%5C%203%260.114%260.342%26-2.034%264.137%5C%5C%204%260.208%260.832%26-1.034%261.069%5C%5C%205%260.241%261.205%26-0.034%260.001%5C%5C%206%260.202%261.212%260.966%260.933%5C%5C%207%260.116%260.812%261.966%263.865%5C%5C%208%260.037%260.296%262.966%268.797%5C%5C%209%260.013%260.117%263.966%2615.729%5C%5C%2010%260.013%260.13%264.966%2624.661%5C%5C%5B1ex%5D%20%26%5CSigma%20p%28x%29%3D1%26E%28x%29%3D%5CSigma%20xp%28x%29%3D5.034%20%5Cend%7Btabular%7D)
![\begin{tabular} {|c|} \left(x-E(x)\right)^2p(x)\\[1ex] 0.127\\0.228\\0.341\\0.472\\0.222\\0.000\\0.188\\0.448\\0.325\\0.204\\0.321\\[1ex]\Sigma\left(x-E(x)\right)^2p(x)=2.876 \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%0A%7B%7Cc%7C%7D%0A%5Cleft%28x-E%28x%29%5Cright%29%5E2p%28x%29%5C%5C%5B1ex%5D%0A0.127%5C%5C0.228%5C%5C0.341%5C%5C0.472%5C%5C0.222%5C%5C0.000%5C%5C0.188%5C%5C0.448%5C%5C0.325%5C%5C0.204%5C%5C0.321%5C%5C%5B1ex%5D%5CSigma%5Cleft%28x-E%28x%29%5Cright%29%5E2p%28x%29%3D2.876%0A%5Cend%7Btabular%7D)
The standard deviation is given by

Therefore, the range of values
containing the usual numbers of girls in 10 births is given by:

Based on the result, 1 girl in 10 births is an unusually low
number of girls because 1 is not within the normal range of values of number of girls per 10 births.
Answer:
5.76
Step-by-step explanation:
Formula bh
3.2 x 1.8=5.76
Step-by-step explanation:
try this option (see the attachment), all the correct answers are marked with colour.