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3 years ago

Find the coordinates of the midpoint of the segment whose endpoints are H(10, 7) and K(8, 11).

Mathematics

1 answer:

Nookie1986 [14]3 years ago

8 0

Answer: (9, 9)

Step-by-step explanation:

$\left(\frac{10+8}{2}, \frac{7+11}{2} \right)=\boxed{(9, 9)}$

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Can someone PLEASE help?? asap

castortr0y [4]

Step-by-step explanation:

sin(s+t) = sin(s)+cos(t) which results

(sin(s)×cos(t))/(cos(s)cos(t)) + (cos(s)×sin(t))/(cos(s)cos(t))

knowing that tan=sin/cos and that cos/cos=1 and sin/sin=1

resulting tan s ×1 + tan t × 1 = tan s + tan t

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2 years ago

Please find the least common denominator for 3/8 <br> 5/12

andriy [413]

Answer:

Step-by-step explanation:

Given two fractions $\frac{3}{8}$ and $\frac{5}{12}.$

Factor the denominators of both fractions:

$8=2\cdot 4=2\cdot 2\cdot 2\\ \\12=2\cdot 6=2\cdot 2\cdot 3$

You can see that two digits 2 are the same in both denominators and there are two more factors: 2 in number 8 and 3 in number 12.

Thus, the least common denominator for $\frac{3}{8}$ and $\frac{5}{12}$ is

$2\cdot 2\cdot 2\cdot 3=24$

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4 years ago

What is the focus of the parabola? y=−1/4x2−x+3

alex41 [277]

Answer: Focus = (-2, 3)

<u>Step-by-step explanation:</u>

$y=-\dfrac{1}{4}x^2-x+3\\\\\rightarrow a=-\dfrac{1}{4},\ b=-1$

First let's find the vertex. We do that by finding the Axis-Of-Symmetry:

$AOS: x=\dfrac{-b}{2a}\quad =\dfrac{-(-1)}{2(\frac{-1}{4})}=\dfrac{1}{-\frac{1}{2}}=-2$

Then finding the maximum by inputting x = -2 into the given equation:

$y=-\dfrac{1}{4}(-2)^2-(-2)+3\\\\y=-1+2+3\\\\y=4$

The vertex is: (-2, 4)

Now let's find p, which is the distance from the vertex to the focus:

$a=\dfrac{1}{4p}\\\\\\-\dfrac{1}{4}=\dfrac{1}{4p}\\\\\\p=-1$

The vertex is (-2, 4) and p = -1

The focus is (-2, 4 + p) = (-2, 4 - 1) = (-2, 3)

3 0

3 years ago

Can someone help on this?

Vika [28.1K]

Answer:

part A: answer c

part B: 4

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4 years ago

Read 2 more answers

Solve -103 = 6 x + 17

Naily [24]

X=-20 hope it helps

7 0

3 years ago