Answer: -3 and 5
<u>Step-by-step explanation:</u>
Let x represent the 1st digit and y represent the 2nd digit. Then,
Eq 1: 2x + 3y = 9 → 3(2x + 3y = 9) → 6x + 9y = 27
Eq 2: 3x + 2y = 1 → -2(3x + 2y = 1) → <u>-6x - 4y = -2</u>
5y = 25
y = 5
Substitute y = 5 into either of the original equations to solve for x:
2x + 3y = 9
2x + 3(5) = 9
2x + 15 = 9
2x = -6
x = -3
Check (using the other original equation):
3x + 2y = 1
3(-3) + 2(5) = 1
-9 + 10 = 1
-1 = 1
A complex number has a real and an imaginary part
is a complex number
A complex number is represented as:
Where:
<em /><em> real</em>
<em /><em> imaginary</em>
<em />
By comparing the options to ;
and
are not complex numbers
This is so because they do not have imaginary parts
However,
is a complex number
Because; 9i is imaginary
Read more about complex numbers at:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
3^3+14*y-(25*y-13)-(y+7*y-9*y)=0
Equation at the end of step 1
((3³ + 14y) - (25y - 13)) - -y = 0
Pull out like factors :
40 - 10y = -10 • (y - 4)
Equation at the end of step3:
-10 • (y - 4) = 0
STEP4:
Equations which are never true:
Solve : -10 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation:
Solve : y-4 = 0
Add 4 to both sides of the equation :
y = 4
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