It is given in the question that, A commercial airline makes a flight each day from New York to Paris .
So in a week, the airline makes 7 flights .
And the aircraft seats 524 passengers, and serves 2 meals 2 each passenger per flight .
It means, for one passenger, one flight , aircraft serves 2 meals.
So for 524 passengers, 7 flights, aircraft serves
See the attached picture:
1st find the median, which would be the middle of the data set. Since there are 9 numbers the median would be the middle number of the set, this would give you the same amount of numbers on each side of it. The numbers to the left would be the lower and the numbers on the right would be the upper
so in the given data set the median is 29
the lower quartile is the median of the lower numbers, in this case the numbers below 29 are 20, 22 , 25, 28
since there is an even amount of numbers you need to add the 2 middle numbers together and divide by 2 to find the lower quartile so 22 +25 = 47, 47 / 2 = 23.5 this is the lower quartile
the upper quartile is found the same way, but using the upper numbers so in this case using 30, 32, 33 , 34
add the 2 middle numbers 32 +33 = 65 divide by 2 = 65/ 2 = 32.5 this is the upper quartile
the inter quartile range is subtracting the lower quartile from the upper quartile: 32.5 - 23.5 = 9
9 is the inter quartile range
Firstly let's find the dimension of this large rectangle:(given)
Area of Rectangle = 660 x 66 =43,560 ft²
And we know that 1 acre = 43,560 ft², then each rectangle has an area of 1 acre & the 20 acres will correspond to 20 x 43560 = 871,200 ft²
We know that the 20 acres form a rectangle. We need to know what is their disposition:
1) We would like to know the layout of the rectangles since we have 4 possibilities FOR THE LAYOUTS
Note that W=66 & L=666 = 43,956 ft²/ unit )
lay out shape could be either:(in ft)
1 W by 20 L (Final shape Linear 66 x 13320 = 879,120) or
2 W by 10 L (Final shape Stacked 132 x 6660 = 879,120) or
4 W by 5 L (Final shape Stacked 264 x 3330 = 879,120) or
2) We would like to know the number of participants so that to allocate equal space as well as the pedestrian lane, if possible, if not we will calculated the reserved space allocated for pedestrian/visitors)
3) Depending on the shape given we will calculate the visitor space & we will deduct it from the total space to distribute the remaining among the exhibitors.
4) (SUGGESTION) Assuming it's linear, we will reserve
20ft x 13320 ft = = 266,400 ft² and the remaining 612,720 ft² for exhibitors
5) Depending on the kind of the exhibition, we will divide the 612,720 ft² accordingly
6) How can we select the space allocated for each exhibitor:
the 617,720 ft² could be written as a product of prime factors:
612720 = 2⁴ x 3² x 5 x 23 x 37
If you chose each space will be185 ft² , then we can accommodate up to 3,312 exhibitors.
Obviously you can choose any multiple of the prime factors to specify the area allocated & to calculate the number of exhibitors accordingly
Add the absolute values of the ordered pairs.
Answer: - (4 1/4)
Solution:
(6 1/2 + 2 3/4) - 1.5*(4.5/0.5)=
(6 0.5 + 2 0.75) - 1.5*(9)=
(6.5+2.75) - 13.5=
(9.25) - 13.5=
- 4.25=
-(4 0.25)=
-(4 1/4)
