Question

5E%7B3%7D%20yz%20%7B%7D%5E%7B2%7D%20" id="TexFormula1" title="9x {}^{2} y {}^{3} z {}^{5} \div 6x {}^{3} yz {}^{2} " alt="9x {}^{2} y {}^{3} z {}^{5} \div 6x {}^{3} yz {}^{2} " align="absmiddle" class="latex-formula">
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Answer 1

Answer:

3y²z³ / 2x

Step-by-step explanation:

we can take one term at a time:

9/6 can be simplified to 3/2

x²÷x³ = x^-1 which equals $\frac{1}{x}$

y³÷y = y²

z⁵÷z² = z³

put it all together:

3·$\frac{1}{x}$·y²·z³ / 2  or

3y²z³ / 2x