5E%7B3%7D%20yz%20%7B%7D%5E%7B2%7D%20" id="TexFormula1" title="9x {}^{2} y {}^{3} z {}^{5} \div 6x {}^{3} yz {}^{2} " alt="9x {}^{2} y {}^{3} z {}^{5} \div 6x {}^{3} yz {}^{2} " align="absmiddle" class="latex-formula">
1 answer:
Answer:
3y²z³ / 2x
Step-by-step explanation:
we can take one term at a time:
9/6 can be simplified to 3/2
x²÷x³ = x^-1 which equals
y³÷y = y²
z⁵÷z² = z³
put it all together:
3· ·y²·z³ / 2 or
3y²z³ / 2x
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