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ss7ja [257]
3 years ago
7

5E%7B3%7D%20yz%20%7B%7D%5E%7B2%7D%20" id="TexFormula1" title="9x {}^{2} y {}^{3} z {}^{5} \div 6x {}^{3} yz {}^{2} " alt="9x {}^{2} y {}^{3} z {}^{5} \div 6x {}^{3} yz {}^{2} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
dexar [7]3 years ago
8 0

Answer:

3y²z³ / 2x

Step-by-step explanation:

we can take one term at a time:

9/6 can be simplified to 3/2

x²÷x³ = x^-1 which equals \frac{1}{x}

y³÷y = y²

z⁵÷z² = z³

put it all together:

3·\frac{1}{x}·y²·z³ / 2  or

3y²z³ / 2x

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4 years ago
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A food packet is dropped from a helicopter and is modeled by the function f(x) = −15x2 + 6000. The graph below shows the height
melisa1 [442]

General Idea:

Domain of a function means the values of x which will give a DEFINED output for the function.

Applying the concept:

Given that the x represent the time in seconds, f(x) represent the height of food packet.

Time cannot be a negative value, so

x\geq 0

The height of the food packet cannot be a negative value, so

f(x)\geq 0

We need to replace -15x^2+6000 for f(x) in the above inequality to find the domain.

-15x^2+6000\geq 0 \; \;  [Divide \; by\; -15\; on\; both\; sides]\\ \\ \frac{-15x^2}{-15} +\frac{6000}{-15} \leq \frac{0}{-15} \\ \\ x^2-400\leq 0\;[Factoring\;on\;left\;side]\\ \\ (x+200)(x-200)\leq 0

The possible solutions of the above inequality are given by the intervals (-\infty , -2], [-2,2], [2,\infty ). We need to pick test point from each possible solution interval and check whether that test point make the inequality (x+200)(x-200)\leq 0 true. Only the test point from the solution interval [-200, 200] make the inequality true.

The values of x which will make the above inequality TRUE is -200\leq x\leq 200

But we already know x should be positive, because time cannot be negative.

Conclusion:

Domain of the given function is 0\leq x\leq 200

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3 years ago
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