P(A)= 4+5+6= 15/2= 75%
P(B)= 6+4=10 5/10= 50%
P(C)= 5+4=9 6/9= 66.6%
His weight would be 136-178 lbs. i dont know how to get the exact but that is the approx
The t-distribution has n - 1 degrees of freedom, where n is the sample size.
In this case n = 20. So the required number of degrees of freedom is:
20 - 1 = 19.
The answer is: 19 degrees of freedom.